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3 years ago

How can you write the expression 7(b – 2) in words?

Mathematics

2 answers:

mash [69]3 years ago

6 0

Answer:

Option E

Step-by-step explanation:

Let's check

Difference of b-2
It has multiplied with 7

So the expression becomes 7(b-2)

m_a_m_a [10]3 years ago

3 0

Solution:

Let's verify each option to see which is correct.

Option A

Two subtracted from the quotient of seven divided by b.

=> 7/b - 2 = 7(b - 2) [False]

Option B

Seven added to difference of b minus two.

=> 7 + (b - 2) = 7(b - 2) [False]

Option C

The quotient of seven divided by b minus two.

=> 7/b - 2 = 7(b - 2) [False]

Option D

Two subtracted from seven times b

=> 7b - 2 = 7(b - 2) [False]

Option E

The product of seven and the difference of b minus two

=> 7 x (b - 2) = 7(b - 2) = 7(b - 2) [True]

Option E is correct.

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The area of a rectangular carpet is 252 square feet. The length is nine feet more than the width. Find the length and the width

Whitepunk [10]

Answer:

<h3>Length = 30 feet </h3><h3>Width = 21 feet </h3>

Given - Length is nine feet more

Area is 252

To find -  Value of length and width

Solution- 

let the width of the carpet be X

therefore length = 9 + X

Area of carpet = Length * width

252 = (9+x) * X

252 = 9x + x²

Solving the equation by splitting middle term

x² + 9x - 252 = 0

x²- 21x + 12x - 252= 0

x ( x - 21) + 12( x - 21) = 0

(x -21)( x + 12) = 0

X = 21 or X = (-12)

Length = 9 + X

= 30 or (-3)

negative is not possible so

length = 30

width = 21

3 0

2 years ago

Find x. Round to the nearest tenth.

In-s [12.5K]

Answer:

x = 4.9

Step-by-step explanation:

We can use the intersecting chords formula:

(segment piece) x (segment piece) = (segment piece) x (segment piece)

7*7 = 10x

49 = 10x

Divide each side by 10

49/10=10x/10

4.9 = x

8 0

4 years ago

Find the prime factorization for 100.

OleMash [197]

Answer:

100

Step-by-step explanation:

So, the prime factors of 100 are written as 2 x 2 × 5 x 5 or 25*4

8 0

3 years ago

Need some help with indefinite integrals pleasee

goldenfox [79]

Observe that $(x^2+2x+2)'=2x+2$ .

You have that $\int \frac{2x}{x^2+2x+2}\; dx=\int \frac{2x+2-2}{x^2+2x+2}\; dx=\int \frac{2x+2}{x^2+2x+2}\; dx+\int \frac{1}{x^2+2x+2}\; dx=I_1+2I_2$ .

To compute $I_1$ you set $y=x^2+2x+2$ , so $dy=2x+2\; dx$ . Therefore, $I_1=\int \frac{1}{y}\; dy=\ln |y|=\ln |x^2+2x+2|=\ln (x^2+2x+2)$ .

For $I_2$ observe that $x^2+2x+2=(x+1)^2+1$ . Let $y=x+1$ . Then $dy=dx$ and $I_2=\int \frac{1}{y^2+1}=\arctan y=\arctan (x+1)$ .

So, $\int \frac{2x}{x^2+2x+2}=\ln (x^2+2x+2)+2\arctan (x+1)+c$ .

8 0

4 years ago

A manufacturing firm, specialising in making widgets, has overhead expenses (wages, utilities etc) of

7nadin3 [17]

C = 150000 + 17n

where,

C = Total Cost per year = Fixed Cost + Variable Cost

n = Number of Widgets produced each year

17n = Variable Cost

150000 = Fixed Cost

6 0

4 years ago