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LekaFEV [45]
2 years ago
7

You pick a card at random. Without putting the first card back, you pick a second card at random. 5 6 7 What is the probability

of picking an even number and then picking an even number?
Mathematics
2 answers:
Mashutka [201]2 years ago
8 0

Answer:

The probability of picking a 7 as the first card is 4 out of 52 or 1/13. The probability of picking a 5 as the second card is 4 out of 51. For both to happen, we multiply and get about .00603318

Thanks!

Arte-miy333 [17]2 years ago
4 0

person above me is correct

Step-by-step explanation:

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Solve the equation for x
Rasek [7]

Answer:

the answer is 5

Step-by-step explanation:

2x/5 - 9 = -7

2x/5      = -7 + 9

2x/5      = 2

2x         = 2 * 5

2x         = 10

x            = 10/2

x            = 5

5 0
3 years ago
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A pool is filling up at a rate 7 gallons per minute. which equation best represents y, the total amount in the pool after x minu
antiseptic1488 [7]

B. y = 7x

7x is the steady rate of 7 gallons per minute. The number of minutes can also be plugged into x to find the volume of the pool after x minutes.

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3 years ago
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How much would $200 invested at 6% interest compounded annually be worth after 6 years? Round your answer to the nearest cent.
Neko [114]
A=P(1+ \frac{r}{n})^{nt}
A=future amount
P=present amount
r=rate in decimal form
n=number of times per year to be compounded
t=time in years

so
P=200
r=0.06
n=1
t=6

evaluate to find A
A=200(1+ \frac{0.06}{1})^{(1)(6)}
A=200P(1.06)^{6}
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6 0
3 years ago
An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
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Paul [167]

Answer:

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Step-by-step explanation:

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