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devlian [24]
3 years ago
8

Find an equation of a square root curve of the form

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

Answer:

  y = √(5x+34)

Step-by-step explanation:

The regression formula that matches a square root function to these points can be worked out by a suitable calculator. The attachments shows the points are matched exactly by the function ...

  y = √(5x+34)

__

If you would like to work this by hand, you can put the (x, y) point values into the proposed equation and see what the coefficients need to be:

  y = √(ax +b)

  7 = √(3a +b)   ⇒   49 = 3a +b

  8 = √(6a +b)   ⇒   64 = 6a +b

Subtracting the first equation from the second, gives ...

  (64) -(49) = (6a +b) -(3a +b)

  15 = 3a   ⇒   a = 5

  49 = 3(5) +b   ⇒   b = 34

You might be interested in
Find the approximate area of the regions bounded by the curves y = x/(√x2+ 1) and y = x^4−x. (You may use the points of intersec
Finger [1]

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

<h3>How to determine the approximate area of the regions bounded by the curves</h3>

In this problem we must use definite integrals to determine the area of the region bounded by the curves. Based on all the information given by the graph attached below, the area can be defined in accordance with this formula:

A = A₁ + A₂                                                                (1)

A₁ = ∫ [g(x) - f(x)] dx, for x ∈ [- 0.786, 0]                   (2)

A₂ = ∫ [f(x) - g(x)] dx, for x ∈ [0, 1.151]                       (3)

g(x) = x⁴ - x                                                               (4)

f(x) = x / √(x² + 1)                                                      (5)

Then, we proceed to find the integrals:

∫ g(x) dx = ∫ x⁴ dx - ∫ x dx = (1 / 5) · x⁵ - (1 / 2) · x²                          (6)

∫ f(x) dx = ∫ [x / √(x² + 1)] dx = (1 / 2) ∫ [2 · x / √(x² + 1)] dx = (1 / 2) ∫ [du / √u] = √u = √(x² + 1)                                                                                  (7)

And the complete expression for the integral is:

A = A₁ + A₂                                                                                      (1b)

A₁ = (1 / 5) · x⁵ - (1 / 2) · x² - √(x² + 1), for x ∈ [- 0.786, 0]               (2b)

A₂ = √(x² + 1) - (1 / 5) · x⁵ + (1 / 2) · x², for x ∈ [0, 1.151]                  (3b)

A₁ = 0.023

A₂ = 0.783

A = 0.023 + 0.783

A = 0.806

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

To learn more on definite integral: brainly.com/question/14279102

#SPJ1

6 0
2 years ago
Write an expression that uses addition,subtraction, multiplication and division and only negative numbers that has the same valu
Assoli18 [71]

Answer:

1+1-1*1/1=1

Step-by-step explanation:

1+1-1*1/1=1

3 0
4 years ago
at a ice cream shop the ratio of sugar cones sold to waffle cones sold is 10:7. if there are 40 sugar cones sold. how many waffl
Korvikt [17]
40/10=4
4*7=28
so answer is 28
8 0
3 years ago
Before we can make the mashed potatoes, we need to boil some water. The water starts out at room temperature, 70° F, and increas
Karolina [17]

Answer:

Part a) y=50t+70

Part b) t=2.84\ min

Step-by-step explanation:

Part a) Create a linear equation

Let

t ----> the time in minutes

y ---> the temperature in °F

we know that

The linear equation in slope intercept form is equal to

y=mt+b

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

The slope m is equal to

m=50\° F\ per\ minute

The y-intercept is

b=70\° F

substitute

y=50t+70

Part b) How many minutes until the water boils at 212° F?

For y=212° F

substitute in the linear equation and solve for t

212=50t+70

50t=212-70

50t=142

t=2.84\ min

6 0
3 years ago
How do I do this? I’m not really sure. Anyways thank you!
Sholpan [36]

Answer:

?

Step-by-step explanation:

4 0
3 years ago
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