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mrs_skeptik [129]
3 years ago
8

Harold bought 20 toys for his nieces and nephews. The least expensive toy cost $6.19, and the most expensive toy cost $9.81. Whi

ch is the best estimate for the total amount Harold spent on the toys he bought for his nieces and nephews?
Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

160 dollars

Step-by-step explanation:

So you would add 6.19 and 9.81 together. Then divide it by 2.  You would get 8. Then multiply it by 20 and you would get 160 dollars

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Round 231469.335329 to the nearest thousand
malfutka [58]

Answer: 231,469.335

Step-by-step explanation:

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Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?
zhuklara [117]

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

3.30 = 3.30

4 0
3 years ago
Solve the inequality <br> 29-2(3-5w) 13
valentinak56 [21]

Answer:

29-2(2w)13

29-2(26w)

29-52w

w=52÷29

7 0
3 years ago
The lengths of the diagonals of a rhombus are 4x and 8x. What algebraic expression gives the perimeter of the rhombus?
Marizza181 [45]

Answer:

Approximately 17.88x or 8x\sqrt{5}

Step-by-step explanation:

Use pythagorean formula. In a rhombus the diagonals bisect each other and they are perpendicular, so you could have a right triangle with legs of 2x and 4x, the hypoteneuse would then be \sqrt{(2x)^{2} +(4x)^{2} }= \sqrt{4x^{2} +16x^{2}} which is approximately 4.47x. In a rhombus all 4 sides are the same, so multiply that by 4 and you get the perimeter. 4(4.47x) = 17.88x  or if you simplify the radical instead it's 8x\sqrt{5}

4 0
3 years ago
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2
nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}

So, our solutions are:

x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}

4 0
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