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mrs_skeptik [129]
3 years ago
8

Harold bought 20 toys for his nieces and nephews. The least expensive toy cost $6.19, and the most expensive toy cost $9.81. Whi

ch is the best estimate for the total amount Harold spent on the toys he bought for his nieces and nephews?
Mathematics
1 answer:
nikklg [1K]3 years ago
8 0

Answer:

160 dollars

Step-by-step explanation:

So you would add 6.19 and 9.81 together. Then divide it by 2.  You would get 8. Then multiply it by 20 and you would get 160 dollars

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Help....................
Romashka-Z-Leto [24]

Answer:

The interquartile range is <em>50.</em>

Step-by-step explanation:

To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1  </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>.  Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>.  Therefore, <u><em>50</em></u><em> is our answer.</em>

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2 years ago
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PLS ANSWER THIS IM IN A HURRY
den301095 [7]

Answer:

14.14 i hope this helps lol ;)

6 0
3 years ago
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Simply this algebraic expression y-3/3+12
kondaur [170]

Answer:

add 12 +9 because i had that same answer on my quiz last week

3 0
3 years ago
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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
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What is the value of x?
liq [111]
An exterior angle is equal to the sum of the 2 non adjacent angles. In this case

100 = x + 70 Subtract 70
x = 100 - 70
x = 30
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3 years ago
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