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Vinvika [58]
3 years ago
5

Which type of line is shown in the illustration below?

Mathematics
2 answers:
AysviL [449]3 years ago
6 0

Answer: B. perpendicular lines because they intersect at a right angle, making them perpendicular.

Karolina [17]3 years ago
3 0

Answer:

None of the above

Step-by-step explanation:

Parallel Lines are not shown in this triangle and it is impossible for a triangle to have parallel lines due to its shape. Perpendicular lines are not shown either. Skew lines are only in 3d models and shapes. This is a 2d shape.

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5. Find the 34th term in the arithmetic sequence 9, 6, 3, <br> A. 90<br> B. -90<br> C.-57<br> D. 108
mafiozo [28]

Answer:

B. -90

Step-by-step explanation:

a1=9; d=-3

a34=9-3(33-1)=-90

8 0
3 years ago
Find the slope . (5,8) and (-4,6) . can someone help plz
nadya68 [22]

An

2/9 is the answer

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve each equation using the quadratic formula. 4x^2-13x+3
Mazyrski [523]

Answer:

( 4 x − 1 ) ( x − 3 )

Step-by-step explanation:

Factor by grouping.

4 0
4 years ago
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You buy 3.18 pounds of oranges, 1.25 pounds of peaches, and 1.96 pounds of grapes. What is your total bill
BabaBlast [244]

Answer:

$6.39

Step-by-step explanation:

Just add the cost of everything

3.18 + 1.25 + 1.96 = 6.39

4 0
3 years ago
Read 2 more answers
In Exercises 23–36, solve the system using either Gaussian elimina- tion with back-substitution or Gauss-Jordan elimination. 23.
Luba_88 [7]

Answer:

23) x= 3, y = 4

24) Any (x,y) values where x = 1.5 - 2y

Step-by-step explanation:

For the first system(23), it goes like this

[1 2 | 7]

[2 1 | 8]

We need to do L2 = L2 - 2L1, so now it is

[1 2   | 7]

[0 -3 |-6]

So, now we have:

-3y = -6 *(-1)

3y = 6

y = 2

x + 2y = 7

x + 4 = 7

x = 3

Now for system 24, we have:

[-1 2 | 1.5]

[2 -4| 3]

We do L2 = L2 + 2L1, so we have:

[-1 2 | 1.5]

[0 0| 0]

So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.

5 0
3 years ago
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