Original molarity was 1.7 moles of NaCl
Final molarity was 0.36 moles of NaCl
Given Information:
Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity
Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity
1. Solve for the molarity of the original (concentrated) solution.
Molarity (M) = moles of solute (mol) / liters of solution (L)
Convert the given information to the appropriate units before plugging in and solving for molarity.
Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)
2. Solve for the molarity of the final (diluted) solution.
Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.
Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution
Molarity (M) of the final solution = 0.36 M NaCl
I hope this helped:))
Thw answer is PHj78 JJ CP30 R2D2
Filter flasks are
also known as vacuum, suction or the Buchner flasks. They have thick walls and also
have a short glass tube. The thick walls are designed to enable the filter withstand
high pressures of vacuum applied to filter substances. Generally this is used
for filtering.
While the Erlenmeyer flask
also called as a conical flask, is a titration flask which consists of a
conical body, a flat bottom, and round neck. This is used for used for general
uses such as mixing, titrations, preparation of cultures, for
recrystallization, and for supporting filter funnels.
<span>Lastly, the Volumetric flasks are graduated flasks which having markings
for different volumes. They are calibrated accurately for a specific amount of
liquid that can be contained in it hence this is specially used for storing
precise amounts of liquid. </span>
Answer:
C
Explanation:
b/c when copper and zinc metal are addedto solution,then the solution will be consider under redox reaction
Answer:
mass ( g ) = 348 g
Explanation:
First you know : M = mole / volume (L)
in question you have the M and V and the formula of SUBSTANCE ( KF )
first you get the number of mole from equation above
so 3 = no of mole / 2
no of mole = 3 × 2 = 6 moles
and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )
so you have already calculate the moles and you can know the MW from the Question
Mw of KF = 39 + 19 = 58
so n = mass / MW
so 6 = mass / 58
mass ( g ) = 348 g
GOOD LUCK
