Answer:
The answer to your question is 1.25 M
Explanation:
Data
Molarity 1 = ?
Volume 1 = 60 ml
Molarity 2 = 0.5 M
Volume 2 = 150 ml
Process
1.- Write the dilution formula
Molarity 1 x Volume 1 = Molarity 2 x Volume 2
-Solve for Molarity 1
Molarity 1 = Molarity 2 x Volume 2 / Volume 1
-Substitution
Molarity 1 = (0.5)(150) / 60
-Simplification
Molarity = 75 / 60
-Result
Molarity = 1.25 M
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Answer:
Explanation:
Hello!
In this case, since the average rate of reaction is computed as a change given by:
![r=\frac{\Delta [NH_4NO_2 ]}{\Delta t}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B%5CDelta%20%5BNH_4NO_2%20%5D%7D%7B%5CDelta%20t%7D)
In such a way, given the concentrations at the specified times, we plug them in to obtain:
Whose negative sign means the concentration decreased due to the decomposition.
Best regards!
Answer:
1.03 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
30.0 mL (0.0300 L) of 0.500 M HCl react.
0.0300 L × 0.500 mol/L = 0.0150 mol
Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl
The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.
Step 4: Calculate the molar concentration of NaOH
0.0150 moles of NaOH are in 14.5 mL (0.0145 L).
M = 0.0150 mol/0.0145 L = 1.03 M
