1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna11 [10]
3 years ago
5

1 What is the mass of 0.328 mol of CO2?

Chemistry
2 answers:
Yuri [45]3 years ago
5 0
A practical chemical unit for handling atoms and molecules. Since atoms and molecules are so small, it is impossible to handle and count atoms and molecules individually. Therefore, the Chemists devised a special unit to describe very large number of atoms, ions and molecules and it is called mole and is abbreviated as mol.

Crank3 years ago
3 0

Answer:

  • use this conversation units to help you hope it helps

You might be interested in
Which of the following bases can remove a proton from formic acid in a reaction that favors products?
Debora [2.8K]
Hydroxide ion is a strong  and would react with H+ to form water 

OH-+H+---->H2O
7 0
3 years ago
What grey rock that has crinoids and brachiopods reacts to hydrochloric acid?
Anon25 [30]
The rock is limestone, I hope this helps!!
5 0
3 years ago
Read 2 more answers
Which of the following NOT a principle of deep ecology, according to Arne Naess? All life has intrinsic value Environment must b
motikmotik

Answer:

On the picture are all principles cited on wikipedia.

Explanation:

So the answer is

1. Environment must be exploited to improve living standards

2. Flourishing human and nonhuman life depends on diversity of life forms

5 0
4 years ago
In an experiment, 34.8243g of copper (II) nitrate hydrate, Cu(NO3)2•zH2O was heated to a constant mass of 27.0351g. Calculate th
Leto [7]

Answer:

1) The mass of water lost = 7.7892 grams

2) Z = 3: Cu(NO3)2*3H2O

Explanation:

<u>Step 1: </u>Data given

Mass of copper (II) nitrate hydrate, Cu(NO3)2•zH2O = 34.8243 grams

Mass of substance after heating = 27.0351 grams

Molar mass of Cu(NO3)2 = 187.56 g/mol

Molar mass of H2O = 18.02 g/mol

<u>Step 2:</u> Calculate mass of water

The mass of water is the mass lost after heating.

Mass water = 34.8243 - 27.0351 = 7.7892 grams of water

<u>Step 3:</u> Calculate moles of Cu(NO3)2

Moles Cu(NO3)2 = Mass Cu(NO3)2 / Molar mass Cu(NO3)2

Moles Cu(NO3)2 = 27.0351 grams / 187.56 g/mol

Moles Cu(NO3)2 = 0.144 moles

<u>Step 4:</u> Calculate moles of H2O

Moles H2O = 7.7892 grams / 18.02 g/mol

Moles H2O = 0.432 moles

<u>Step 5:</u> Calculate Z

z = moles H2O / moles Cu(NO3)2

Z = 0.432/0.144

Z = 3

This means we have 3 water molecules in the formula. This makes the formula ofthe hydrate: Cu(NO3)2*3H2O

5 0
3 years ago
sample of carbon dioxide is contained in a 500.0 mL flask at 0.955 atm and 15.9 ∘ C. How many molecules of gas are in the sample
Ray Of Light [21]
Hope this helped, if you found it helpful please mark me as brainliest or give thanks :)

5 0
4 years ago
Read 2 more answers
Other questions:
  • A cyclist rode at an average speed of 10 mph for 15 miles. How long was the ride?
    13·2 answers
  • The normal freezing point of a certain liquid
    9·1 answer
  • Method that used to separate kerosine and water?
    9·2 answers
  • For the following reaction, 16.2 grams of carbon dioxide are allowed to react with 45.0 grams of potassium hydroxide. carbon dio
    11·1 answer
  • Pb(OH)2 + _HCI → __ H2O + _<br>PbCl2​
    6·1 answer
  • Cellular respiration role during water cycle
    6·1 answer
  • . Now Sara comes along, and she is the exact same size as you. However, she is even stronger than you are! When she pulls you in
    5·1 answer
  • Which TWO substances are reactants in the chemical reactions of cellular respiration
    5·2 answers
  • Determine the empirical and molecular formulas for a compound that has 10 pa a molar mass of 300 g/mol, and is 60.0% C, 12% H, a
    12·1 answer
  • How many grams are in 8.3 moles of CaCl2?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!