For the purpose we will use solution dilution equation:
c1xV1=c2xV2
Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.
c1 = 70%
c2 = 25%
V1 = ?
V2 = 1000 mL
When we plug values into the equation, we get following:
70 x V1 = 25 x 1000
V1 = 333.33 mL
V(H2O)=V2-V1= 1000-333.33=666.67 mL
Answer: 88g
Explanation:
11 moles H2 = 11 mole H2O = 5.5 moles O2 = 16*5.5 g
We are given the balanced equation 2NaF + Ca10(PO4)6(OH)2 → Ca10(PO4)6F2 + 2NaOH. The fluorapatite is the product together with sodium hydroxide. The ions involved are (PO4) 3-, Ca 2+ and <span>F-. We add the charges and check if the sum is zero, 2*10+-3*6+-1*2 =0. the zero sum tells that the compound has zero charge or neutral</span>
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Explanation:
The answer to questions are
A) 4
B) 3
C) 5
D) 3
E) 3