Answer:
the 
of students in the class are 
students
the 
of students here in class today are 
Step-by-step explanation:
Let
x-------------> total students in the class
y------------- >number of the students here in class
so
we know that
the interval solution for x is all whole numbers belong to the interval
![[0,49]](https://tex.z-dn.net/?f=%5B0%2C49%5D)
the solution will be a number belonging to the interval such that when multiplying by it gives me a whole number
see the attached excel table
the of students in the class are students
the of students here in class today are
You could say u skip every 3 or what ever the odd number may be so like 3,7,9, numbers like that
Answer:
The number of child tickets sold by the amusement park is 189.
Step-by-step explanation:
Let A represent the number of adult tickets and C represents the number of child tickets, therefore we have:
3:1 = C:A .................... (1)
Where;
C = ?
A = 63
Substituting for the value into equation (1), we have:
3:1 = C:63
This can be converted to solve for C as follows:
3 / (3 + 1) = C / (C + 63)
3 / 4 = C / (C + 63)
0.75 = C / (C + 63)
0.75(C + 63) = C
0.75C + (0.75 * 63) = C
0.75C + 47.25 = C
47.25 = C - 0.75C
47.25 = 0.25C
C = 47.25 / 0.25
C = 189
Therefore, the number of child tickets sold by the amusement park is 189.
Answer:
179, 180, 181
Step-by-step explanation:
a +a +1 +a +2 =540
3a +3 =540
3a =540 - 3
3a=537
a=537 :3
a=179 (the first number
b=179 +1 =180 (the second number
c=179 +2 =181 (the third number
Answer:
Day 13
Step-by-step explanation:
The question can be represented with a geometric sequence
Where,
a = 5
Common ratio , r = 2
v(t) = a * r^(t - 1)
v(t) = 5 * 2^(t-1)
20,000 = 5 * 2^(t-1)
Divide both sides by 5
20,000 / 5 = 5 * 2^(t-1) / 5
4,000 = 2^(t-1)
2^12 = 2^(t-1)
12 = t - 1
12 + 1 = t
t = 13 days
What would be the day when more than 20,000 people will see the video
Check:
v(t) = 5 * 2^(t-1)
= 5 * 2^(13-1)
= 5 * 2^12
= 5 * 4,096
= 20,480
Therefore,
The day when more than 20,000 people will see the video is day 13
