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yuradex [85]
3 years ago
5

Please slove number 16

Mathematics
2 answers:
kap26 [50]3 years ago
6 0
The answer to your question is A, since 3/12 + 5/12 is 8/12, leaving 4/12 left. (Sorry if I'm confusing)
saveliy_v [14]3 years ago
5 0
A. because 5+3=8 
12-8=4
So 4/12 
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Solve the following system of equations: <br>y=2x + 1 <br>y = -x+4<br><br>x= ?<br>y=?​
patriot [66]

Answer:

x= 1, y=3

Step-by-step explanation:

y= 2x +1

y= -x +4

Those two equation are in a system that means they need to be true in the same time. Just like I would say look for a car that is red and is a truck in this case we look for x and y is true that y = 2x+1 and is true that y= =x+4.

so y= 2x+1 but y is -x+4 so substitute

-x+4 = 2x +1,  add x on both sides

4= 2x+x +1, subtract 1 from both sides

4-1 = 2x +x, combine like terms

3 = 3x , divide both sides by 3

x=1

if x=1 we substitute in y= -1 +4 = 3

4 0
3 years ago
Write the sum of 27+63 as a product of there gcf and a another sum
Sloan [31]

Answer:

27+63=90

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3 0
3 years ago
In response to very high demand, a new bike has been marked up by 25% and is now selling for 210.00. how much was the bike befor
harina [27]
Call the price of the bike before mark up 'x', then we have:

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3 0
3 years ago
Read 2 more answers
Write 4/6 in the lowest terms
dedylja [7]
2/3 is the answer in lowest terms. i hope this helps!
7 0
2 years ago
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Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
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