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N76 [4]
3 years ago
7

Need help quick! What is the product? (-1 2 4) (3 6 1 2 4 0 0 6 2)

Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0

Answer:

[1  26  7]

Step-by-step explanation:

[1  26  7]

one row three column

Mandarinka [93]3 years ago
4 0
<h3>Answer: Second answer choice. \begin{bmatrix}1 & 26 & 7\end{bmatrix}</h3>

==========================================================

Explanation:

We have a 1x3 matrix multiplied with a 3x3 matrix. This is a valid operation since the number of columns in the first matrix matches with the number of rows in the second matrix.

The resulting answer matrix will be 1x3 as it takes the number of rows of matrix A and the number of columns from matrix B, helping forming the answer matrix C.

The answer matrix looks like

C = \begin{bmatrix}x & y & z\end{bmatrix}

where x, y and z are placeholders for actual numbers.

To get the value of x, we apply the dot product of the left matrix with the first column of the right matrix

x = (-1)(3)+(2)(2)+4(0) = -3+4+0 = 1

We'll do a similar set of steps to find y

Apply the dot product on the second column this time

y = (-1)(6)+2(4)+4(6) = -6+8+24 = 26

and the third column as well

z = (-1)(1)+2(0)+4(2) = -1+0+8 = 7

Since x = 1, y = 26 and z = 7, we can say

C = \begin{bmatrix}x & y & z\end{bmatrix}

becomes

C = \begin{bmatrix}1 & 26 & 7\end{bmatrix}

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Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
NEED HELP FAST PLZZ!!!!!!!
adell [148]
The answer is A. 102.  

Have a great day!
4 0
3 years ago
Answer correclty PLZZZ
ioda

Answer: option C is the correct answer

Step-by-step explanation:

The system of linear equations is

10x + 7y = 12 - - - - - - - 1

8x + 7y = 18 - - - - - - - 2

Since the coefficient of y is the same in equation 1 and equation 2, we will eliminate y by subtracting equation 2 from equation 1, it becomes

10x - 8x + 7y - 7y = 12 - 18

2x = -6

x = - 6/2 = - 3

Substituting x = - 3 into equation 1, it becomes

10×-3 + 7y = 12

-30 + 7y = 12

Let the constants be on the right hand side and the term containing y be on the left hand side. It becomes

7y = 12 + 30

7y = 42

y = 42/7

y = 6

C) (−3, 6)

6 0
3 years ago
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