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2 years ago

15

Suppose you know the volume of a pyramid with a rectangular base is 200 cubic units. How could you find a set of dimensions for

the pyramid?

1 answer:

Vinil7 [7]2 years ago

4 0

I tried figuring it out but sorry I can’t help you

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Y=8(x^2+4)+17+-32 in vertex form

Yakvenalex [24]

$y = 8( {x}^{2} + 4) + 17 + ( - 32)$
$y = 8( {x}^{2} + 4) + 17 - 32$
$y = 8 {x}^{2} + 32 + 17 - 32$
$y = 8 {x}^{2} + 17$
compare to the formula:
$y = a( {x}^{2} - h) + k$
$y = 8( {x}^{2} - 0) + 17$
a = 8
h = 0
k = 17

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3 years ago

The function f is a defined by f (x) =x^2+6<br> Find f (3x)

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Step-by-step explanation:

here

f(x)=x^2+6

Now

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2 years ago

6,12,8,15,9,7 what it the interquartile range

nekit [7.7K]

Answer:

5 is the interquartile range

Step-by-step explanation:

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3 years ago

Write the answer in simplest form 1 1/3 ÷ 2/3 =

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Hopes this helps:

Answer: 2

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3 years ago

Read 2 more answers

The sum of two numbers is six, and the difference is 10. Find the numbers.

pashok25 [27]

First no. = x
Second no. = y

Equation Formation
x + y = 6..........equation(i)
x - y = 10...........equation (ii)

x = 6 - y
6 - y - y = 10
6 - 2 y = 10
-2 y = 10 -6
-2 y = 4
y = -2

x = 6 + 2
x = 8

Answer = 8 , -2

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3 years ago