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kolezko [41]
2 years ago
11

Help please I don’t understand

Mathematics
1 answer:
Phantasy [73]2 years ago
3 0

The height of the object after 1 sec is 284 feet

<h3>Equation of height of an object</h3>

Given the equation of height of an object expressed as:

h(t) = -16t^2 + 300t

We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression

h(t) = -16t^2 + 300t

h(1) = -16(1)^2 + 300(1)

h(1) = -16 + 300

h(1) = 284ft

Hence the height of the object after 1 sec is 284 feet

Learn more on maximum height here: brainly.com/question/12446886

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Answer:

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Ratling [72]

Answer:

range = 7.87

X = 62.12, X²= 164.3516

mean = 1.2424

variance = 1.779

standard deviation = 1.33379

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Step-by-step explanation:

a.) The range =

highest number - lowest number

= 7.89 - 0.02

= 7.87

b.) from the attachment I solved for X and X²

∑X = 62.12

∑X² = 164.3516

c.)

the mean = ∑x/n

n = 50

= 62.12/50

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variance =

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= 164.3516 - 77.17788/49

= 87.173712/49

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standard deviation = √σ

= √1.779

= 1.33379

d. coefficient of variation

= σ/mean * 100

= 1.33379/1.2424 * 100

= 107.3559

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professor190 [17]
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