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pshichka [43]
3 years ago
6

While picking thirty apples, Mia noticed that six apples had worm holes and had to be thrown away. What is the ratio of good app

les picked to bad apples picked?
Mathematics
2 answers:
vlada-n [284]3 years ago
7 0

Answer:6:24

Step-by-step explanation:


sergejj [24]3 years ago
3 0
6:24 or and 6/24

this explains the ration of the good apples and the bad apples
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PLEASEE HELL<br> find the solution to the system of equations
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(-3, -4)

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y= -4

so you plus y in for the y=2x+2 equation where you get x=-3

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Han has 10 cubes, each 5 inches on a side. A) Find the total volume of Han’s cubes. Express your answer as an expression using a
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Answer:

A) Vol_10_cubes  = 2*(5^4) inch^3

B) Area_10_cubes = (2^2)*3*(5^3)  inch^2

Step-by-step explanation:

A)The volume of a cube, as all sides are equal:

Vol_cube = (side)^3

side = 5 inches

Vol_cube  = 5^3 inch^3

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10 = 2*5

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B) A cube has six faces, each with area equal to its squared side

Area_cube = 6*(side)^2

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Area_10_cubes = (2^2)*3*(5)^3  inch^2

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3 years ago
Leah gets paid $795 biweekly. What is the recommended monthly rent that she can afford?
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Keith’s dad is 44 years old if this is 4 years less than three times Keith’s age how old is Keith
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An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
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Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

P(e_1)=0.90*0.67=0.603

2) Left knee unsuccessful and right knee successful (X=1).

P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067

3) Right knee unsuccessful and left knee successful (X=1).

P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297

4) Both surgeries are unsuccessful (X=0).

P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033

Then, the mean can be calculated as the expected value:

M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57

The variance can be calculated as:

V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111

3 0
3 years ago
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