Answer:
8P3 = 336
9C4 = 126
Step-by-step explanation:
8P3 = 8! ÷ 5! = 8x7x6 = 336
9C4 = 9! ÷ (5!·4!) = (9x8x7x6) ÷ (4x3x2) = 126
According to the question.
For the fair the organiser ordered 32 rolles of tickets .
though each role has 100 tickets .
so we have to find the total no. of tickets.
So we will multiply 32 with 100.
=> 32× 100=
HOPE IT HELPED YOU..
The sixth term in this problem would have a base of 6^3, which would equal to 213.