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elena55 [62]
3 years ago
10

Find the value of each expression. Show your work. 10^C^4

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0
_nC_r = \frac{n!}{(n - r)!r!}
<span>_1_0C_4 = \frac{10!}{(10 - 4)!4!}
</span>_1_0C_4 = \frac{10!}{6!4!}
_1_0C_4 = \frac{10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1}{6 * 5 * 4 * 3 * 2 * 1 * 4 * 3 * 2 * 1}
_1_0C_4 = \frac{10 * 9 * 8 * 7}{4 * 3 * 2 * 1}
_1_0C_4 = \frac{90 * 56}{12 * 2}
_1_0C_4 = \frac{5040}{24}
_1_0C_4 = 210
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Answer:

<h2>x = 2</h2>

Step-by-step explanation:

2x + 6 = 6 + 2x

4 + 6 = 6 + 4

10 = 10

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1. In which quadrant or on which axis do each of the points (-2,4) , (3,-1) ,(-1,0), (1,2) and (-3,-5) lie? Verify your answer b
pashok25 [27]

Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) lies in the 3rd quadrant

Step-by-step explanation:

Let us revise the signs of the coordinates in each quadrant

  • x and y coordinates are positive in the 1st quadrant
  • x-coordinate is negative and y-coordinate is positive in the 2nd quadrant
  • x and y coordinates are negative in the 3rd quadrant
  • x-coordinate is positive and y-coordinate is negative in the 4th quadrant
  • The general point on the positive part of x-axis is (x , 0), and on the negative part of x-axis is (-x , 0)
  • The general point on the positive part of y-axis is (0 , y), and on the negative part of y-axis is (0 , -y)

Now let us check the points

Point (-2 , 4) ⇒ red point

∵ x = -2 and y = 4

∵ x-coordinate is negative and y-coordinate is positive

∴ Point (-2 , 4) lies in the 2nd quadrant

Point (3 , -1) ⇒ blue point

∵ x = 3 and y = -1

∵ x-coordinate is positive and y-coordinate is negative

∴ Point (3 , -1) lies in the 4th quadrant

Point (-1 , 0) ⇒ green point

∵ x = -1 and y = 0

∵ x-coordinate is negative and y-coordinate is zero

∴ Point (-1 , 0) lies on the negative part of the x-axis

Point (1 , 2) ⇒ purple point

∵ x = 1 and y =2

∵ x and y coordinates are positive

∴ Point (1 , 2) lies in the 1st quadrant

Point (-3 , -5) ⇒ black point

∵ x = -3 and y = -5

∵ x and y coordinates are negative

∴ Point (-3 , -5) lies in the 3rd quadrant

<em>Look to the attached graph for more understand</em>

Learn more:

You can learn more about the four quadrant in brainly.com/question/9381523

#LearnwithBrainly

5 0
3 years ago
Last week, the raito of laptops to desktop sold at a computer store was 2:3. eighteen desktop models were sold. how many laptop
poizon [28]
I think you mean "ratio", not "raito." Ummm... The answer is 30 models that were sold
7 0
3 years ago
Find the linear approximation for f(x) = 12x3 + 3x2 + x + 2 at x= 1.
Alchen [17]

Answer:

y = 43x − 25

Step-by-step explanation:

Evaluate the function at x=1:

f(x) = 12x³ + 3x² + x + 2

f(1) = 12 + 3 + 1 + 2

f(1) = 18

Find the slope of the tangent line at x=1:

f'(x) = 36x² + 6x + 1

f'(1) = 36 + 6 + 1

f'(1) = 43

Point-slope form:

y − y₀ = m (x − x₀)

y − 18 = 43 (x − 1)

Convert to slope-intercept form:

y − 18 = 43x − 43

y = 43x − 25

Graph:

desmos.com/calculator/giumpkkphr

8 0
3 years ago
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