<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
The train is traveling at 165 mph
495/3=165
825/5=165
1155/7=165
1485/9=165
Simple...
you have:
You want to find m-->>>
1.)Isolate m
Leaving you with...
F*
=
Keep isolating m-->>>
Square root to solve what just m is-->>>
=
That is how you solve for m...
Thus, your answer.
Answer:
The maximum value of a function is the place where a function reaches its highest point, or vertex, on a graph.
I hope it helps.