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rusak2 [61]
2 years ago
13

The horizontal cross-sectional shapes of the prism given below are all

Mathematics
2 answers:
Genrish500 [490]2 years ago
6 0
It is true that is the
nekit [7.7K]2 years ago
3 0

A. True

This is the correct answer

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What is 4 radical 3 divided by 2?
Arte-miy333 [17]
3/2 = 6 
6/4= 6/40= 6 .999= ~ 7
5 0
2 years ago
Find the solution of the system of equations<br> shown on the graph.
o-na [289]

Answer:

Answer:(0,3)Step-by-step explanation:The solution in a set of graphs is where they intersect. In this graph, they intersect at (0,3)

4 0
2 years ago
For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a/2.0

3 0
2 years ago
Find 2 numbers a and b such that (a-b)^2 &lt; (a+b)(a-b)&lt; (a+b)^2 Find two numbes a and b such that this is not true
Svet_ta [14]

Suppose for the moment that the inequality holds for all a,b:

(a-b)^2

Expanding everything gives

a^2-2ab+b^2

\implies-ab

In particular, the inequality says that -ab for any choice of a,b. But if a and b>0, then -ab>0 while ab.

So one possible choice of a,b could be a=-1 and b=1. Then we get

(-1-1)^2=4

(-1+1)(-1-1)=2

(-1+1)^2=0

but clearly it's not true that 4.

8 0
3 years ago
I need help on this question <br> pls help yes
galina1969 [7]

The arc length of the semicircle is 5π units

<h3>Calculating length of an arc</h3>

From the question, we are to calculate the arc length of the semicircle

Arc length of a semicircle = 1/2 the circumference of the circle

∴ Arc length of a semicircle = 1/2 × 2πr

Arc length of a semicircle = πr

Where r is the radius

From the given information,

r = 5

∴ Arc length of the semicircle = 5 × π

Arc length of the semicircle = 5π units

Hence, the arc length of the semicircle is 5π units

Learn more on Calculating length of an arc here: brainly.com/question/16552139

#SPJ1

8 0
2 years ago
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