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Bond [772]
2 years ago
13

Triangle A B C is shown. Angle A B C is a right angle. An altitude is drawn from point B to point D on side A C to form a right

angle. The length of A D is 5 and the length of B D is 12.
What is the length of Line segment B C, rounded to the nearest tenth?

13.0 units
28.8 units
31.2 units
33.8 units
Mathematics
1 answer:
Dimas [21]2 years ago
5 0

Answer: 31.2

Step-by-step explanation:

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4/5 y = 8 , how do we solve pls help fast its urgent, I will mark u brainliest
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Answer:

y = 10

Step-by-step explanation:

4/5 y = 8

4/5 y * 5/4 = 8 * 5/4           multiply by reciprocal

y = 10

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A rectangle has a perimeter of 48 feet and a length of 14 feet. what equation can you solve to find the width?
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7 0
3 years ago
A kangaroo hopped \dfrac13 3 1 ? of the distance to the lake with her baby in her pouch. She hopped the remaining 70407040 yards
kogti [31]

Answer:

6 miles.

Step-by-step explanation:

Let x be the total distance hoped by Kangaroo to the lake.

We have been given that a kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch.

She hopped the remaining 7040 yards without her baby in her pouch. This means that 2/3 of total distance (x) is 7040. We can represent this information in an equation as:

\frac{2}{3}*x=7040

Let us solve for x by multiplying both sides of our equation by 3/2.

\frac{3}{2}*\frac{2}{3}*x=\frac{3}{2}*7040

x=3*3520

x=10560

Therefore, the total distance hoped by the kangaroo is 10560 yards.

1 mile = 1760 yards

Let us convert this distance in miles by dividing 10560 yards by 1760.

\text{The kangaroo hoped}=\frac{10560\text{ yards}}{\frac{1760\text{ yards}}{\text{Mile}}}

\text{The kangaroo hoped}=\frac{10560\text{ yards}}{1760}\times \frac{\text{ Mile}}{\text{ yards}}

\text{The kangaroo hoped}=\frac{10560}{1760}\times\text{ Mile}

\text{The kangaroo hoped}=6\text{ Miles}

Therefore, the kangaroo hoped 6 miles to the lake.

3 0
3 years ago
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