As the liquid gets closer to the same temperature as the room, it cools down slower. If you put an glass of hot cocoa in a really cold room, it'll decrease really fast until it's around the same temperature as the room
Answer:
(-5,-2)
(-4,-3)
(-6,-1)
Step-by-step explanation:
-5(x)-2(y)=-7
-4(x)-3(y)=-7
-6(x)-1(y)=-7
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
As per the statement:
The path that the object takes as it falls to the ground can be modeled by:
h =-16t^2 + 80t + 300
where
h is the height of the objects and
t is the time (in seconds)
At t = 0 , h = 300 ft
When the objects hit the ground, h = 0
then;
-16t^2+80t+300=0
For a quadratic equation: ax^2+bx+c=0 ......[1]
the solution for the equation is given by:
On comparing the given equation with [1] we have;
a = -16 ,b = 80 and c = 300
then;
Simplify:
= -2.5 sec and 
= 7.5 sec
Time can't be in negative;
therefore, the time it took the object to hit the ground is 7.5 sec
Answer: No
Step-by-step explanation:
A variable is always denoted with a symbol (commonly x), and a variable means that it can change based on what you plug into the symbol
Constants must always stay the same, so variables can't be constants and constants can't be variables
