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3 years ago

13

A particular line passes through (9,0) and has a negative slope if the Y intercept is a single digit prime number what is the su

m of all possible Y intercepts

1 answer:

dezoksy [38]3 years ago

5 0

Answer:

Step-by-step explanation:

y-intercept = 2, 3, 5, or 7

2+3+5+7 = 17

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How does a tree feel after a hard day at work?

alisha [4.7K]

Answer: Happy that he was able to create more seeds and create more trees!

Step-by-step explanation:

4 0

3 years ago

Performance task A parade route must start And and at the intersections shown on the map. The city requires that the total dista

Flauer [41]

Answer:

A: the proposed route is 3.09 miles, so exceeds the city's limit

Step-by-step explanation:

The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...

a^2 = (12-6)^2 +3^2 = 45

a = √45 = 3√5

and

b^2 = (6 -2)^2 +4^2 = 32

b = √32 = 4√2

Then the total length, in grid squares, is ...

3√5 + 4√2 = 6.7082 +5.6569 = 12.3651

If each grid square is 1/4 mile, then 12.3651 grid squares is about ...

(12.3651 squares) · (1/4 mile/square) = 3.0913 miles

The proposed route is too long by 0.09 miles.

5 0

3 years ago

Simplify the expressions by combining like terms<br><br> 1.5r - 3r + 8r + 2.5r

Tomtit [17]

Answer:

9r

Step-by-step explanation:

1.5r - 3r + 10.5r

10.5r + 1.5r = 12r

12r - 3r = 9r

Final Answer = 9r

5 0

3 years ago

The perimeter of a square with sides measuring 5 inches is _______ inches

Rzqust [24]

Each side is 1.25inches I don't know if this answers your question but i hope it helps

4 0

3 years ago

Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

7 0

4 years ago