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MissTica
3 years ago
14

PLEASE HELP PLEASE HELP IM GIVING BRAINLIEST AND 30 POINTS FOR ANYONE THAT ANSWERS IN 5 MIN

Mathematics
2 answers:
Burka [1]3 years ago
7 0

Answer:

\sf \dfrac{27}{512}

step:

\hookrightarrow \sf (\dfrac{3}{8} )^3

rewrite:

\hookrightarrow \sf (\dfrac{3}{8} )(\dfrac{3}{8} )(\dfrac{3}{8} )

remove parenthesis

\hookrightarrow \sf(\dfrac{9}{64} )(\dfrac{3}{8} )

final answer

\hookrightarrow \sf \dfrac{27}{512}

Monica [59]3 years ago
4 0
(3/8)(3/8)(3/8)=27/512
The first one;27/512
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PLEASE HELP ASAP! WILL GIVE BRAINLEIST!<br> Find the area of the shaded region. Use pi = 3.14
Semmy [17]

Answer:

Step-by-step explanation:

Square

The side length of the square = 8 cm

The area of the square = s^2

The area of the square = 8^2 = 64

Circle

r = d/2

r = 8/2

r = 4

Area of the circle = pi r^2

Area of the circle = 3.14 * 16

Area of the circle = 50.24

Shaded Area

Area of the Shaded area = area Square - Area Circle

                                          = 64 - 40.24

                                          = 23.76

4 0
4 years ago
What is the value of b in the equation 3b + 2(b − 1) = 8?
Ray Of Light [21]
<span>3b + 2(b − 1) = 8
3b + 2b - 2 = 8
5b = 10
b = 2

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7 0
3 years ago
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rusak2 [61]
6.4 is the answer hope this helps
5 0
3 years ago
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Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

Surface area of the star = 4n^{2}

Where n is the radius of the star.

So that;

n = \frac{ 1.8083 * 10^{4} }{2}

   = 0.90415 x 10^{4}

n =  0.90415 x 10^{4} Km

Thus,

Surface area = 4 x (0.90415*10^{4} )^{2}

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4 0
3 years ago
I need help with all 4 of these . And I do need to show work for all of them
malfutka [58]

Answer:


Step-by-step explanation:

11) Profit = Selling price - purchase price - other expenses

= (2000*7)-12780-26=1194

12)  Profit = Selling price - purchase price - other expenses

=52.25(550)-28275-32=430.50=430(after rounding off)

13) Annual interest on bond

=INterest rate on face value of bond for 1 year

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14)Cost of bond

= quoted value (rate)

=3500(80.5)

=2817.50

15) Cost of bond

= quoted value (rate)

=4250(83.5)

=3548.75


3 0
4 years ago
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