Answer:
p=3
Step-by-step explanation:
The given parabola has equation ;
![x^2=12y](https://tex.z-dn.net/?f=x%5E2%3D12y)
The general formula for a parabola is;
![x^2=4py](https://tex.z-dn.net/?f=x%5E2%3D4py)
To find the value of p, we need to compare the coefficient of y in both equations;
![\implies 4p=12](https://tex.z-dn.net/?f=%5Cimplies%204p%3D12)
Divide both sides by 4;
![\implies p=\frac{12}{4}](https://tex.z-dn.net/?f=%5Cimplies%20p%3D%5Cfrac%7B12%7D%7B4%7D)
![\implies p=3](https://tex.z-dn.net/?f=%5Cimplies%20p%3D3)
The answer is
B. -2 and 3
Step-by-step explanation :
Given the expression
x²- 5x + 6 = 0
Firstly we need to find two numbers that when multiplied will give us the constant term 6, and when added will give us the 2nd term 5
These numbers are 3 and 2
Substituting 2x +3x for 5x
x²- (2x+3x)+ 6 = 0
x²-2x-3x+6=0
(x²-2x)-(3x+6)=0
Factoring we have
x(x-2)-3(x-2)=0
x-3=0, x-2=0
x=3, x= 2
3*-2=-6
-6*-2=12
The sequence is a number being multiplied by -2 over and over.
48, -96, 192, -384, 768, etc.
Step-by-step explanation:
Total numbers of pizza toppings = 12
Number of three topping pizzas can be ordered are:
![P^{n}_{k}=\frac{n!}{(n-k)!}](https://tex.z-dn.net/?f=P%5E%7Bn%7D_%7Bk%7D%3D%5Cfrac%7Bn%21%7D%7B%28n-k%29%21%7D)
where = n = number of elements
k = number of elements choosen
n= 12 , k = 3
![\frac{12!}{(12-3)!} =\frac{12\times 11\times 10\times 9!}{9!}= 1,320](https://tex.z-dn.net/?f=%5Cfrac%7B12%21%7D%7B%2812-3%29%21%7D%20%3D%5Cfrac%7B12%5Ctimes%2011%5Ctimes%2010%5Ctimes%209%21%7D%7B9%21%7D%3D%201%2C320)
We calculated the number of permutations. We made this choice because in permutation order of element matters but in combination its not.
Since
and
, we have
![ab=10(2x+5)=20x+50](https://tex.z-dn.net/?f=ab%3D10%282x%2B5%29%3D20x%2B50)
So, the equation becomes
![ab = 6x^2 +11x-10 \iff 20x+50= 6x^2 +11x-10 \iff 6x^2-9x-60=0](https://tex.z-dn.net/?f=ab%20%3D%206x%5E2%20%2B11x-10%20%5Ciff%2020x%2B50%3D%206x%5E2%20%2B11x-10%20%5Ciff%206x%5E2-9x-60%3D0)
The solutions to this equation are 4 and -5/2, so I'm afraid there's a typo in your question.