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2 years ago

X²- 12x + a = (x-b)² Find the Value of a and value of b

Mathematics

1 answer:

maxonik [38]2 years ago

5 0

Answer:

a = 36 , b = 6

Step-by-step explanation:

expand the right side using FOIL and compare coefficients with like terms on left side.

(x - b)²

= x² - 2bx + b² , compare to x² - 12x + a , then

- 2b = - 12 ( divide both sides by - 2 )

b = 6

and a = b² = 6² = 36

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-. Six square-based pyramids fit exactly onto the six faces of a

igor_vitrenko [27]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is the solution to the equation 3x-5=2x+8+x?

Marysya12 [62]

So when solving this you are going to have to solve the equation.
Okay so first thing we need to do is simplify both sides of your equation so:
3x−5=2x+8+x
Simplifying process:
3x+−5=2x+8+x
Combine Like Terms ⇒ 3x−5=(2x+x)+(8)
3x−5=3x+8
3x−5=3x+8
Second thing we are now going to do is subtract 3x from both sides so:
3x−5−3x=3x+8−3x
−5=8
Final step is to add 5 to both sides:
−5+5=8+5
0=13
The answer to your question is "There are no solutions"

6 0

3 years ago

Hi please help me thanksss pls provide workings too thanks :)

anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

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We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

2π

or x=

6n±2

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

4 0

2 years ago

A circle is defined by the equation given below.

Ierofanga [76]

The circle equation is in the format (x – h)2 + (y – k)2= r2, with the center being at the point (h, k) and the radius being "r".

x²+y²-8x-6y+2 =0 -----(a)
(x-4)² = x² - 8x + 16
(y-3)² = y² - 6y + 9

Equation (a) can be rewritten as:
(x-4)² + (y-3)² + 2 - 16 - 9 = 0
(x-4)² + (y-3)² = 23

The coordinates for the center of the circle is: ( 4,3)
The radius is √23=4.8

5 0

3 years ago

The following two points are on a line: (2,3), (-2,5). What is the slope of the line?

8_murik_8 [283]

Answer:

Step-by-step explanation:

slope = rise / run

slope = (5 - 3) / (-2 - 2)

slope = 2 / -4

slope = -2 / 4

slope = -1/2

8 0

1 year ago

X²- 12x + a = (x-b)² Find the Value of a and value of b ​

X²- 12x + a = (x-b)² Find the Value of a and value of b