Yes. A is the right graph because the line must travel through two points: (0 ,1)and(-3, 0)
Answer: 15 hours and 37 minutes
Step-by-step explanation: 6 and 1/2 hours is 6 hours and 30 mins
8 and 2/3 hours is 8 hours and 67 mins
So 8 hours + 6 hours is 14 hours
Since 67 minutes is over an hour, we're going to take 60 minutes from 67, leaving u with 7 minutes
Add the 60 minutes to the 14 hours and you get 15 hours.
Take the 7 minutes and add it to the 30 minutes and you get 37 minutes.
All together the answer is 15 hours and 37 minutes
<span>56f^3 g^2 = 7fg^2(8f^2)
and
70fg^3 = 7fg^2(10g)
</span>Gcf of 56f^3 g^2 and 70fg^3 = 7fg^2
Answer:
Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".
Part A
The definition of the Intersecting Secant-Tangent Theorem is:
"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."
This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".
Mathematically, it can be written as:
Part B
It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:
Thus,
Thus the length of TU=6 inches
