The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
Answer:
The answer is 45.
Step-by-step explanation:
60% of a number is 54, find the original number
54 ÷ 60%
= 54 ÷ 60/100
= 54 * 100/60
= 90
50% of 90 is
90 * 50%
= 90 * 50/100
= 90 * 1/2
= 45
Answer:
64.8
Step-by-step explanation:
Pythagoreon Theroem
a^2 + b^2 = c^2 in this situation it would actually be the opposite, seeing where the "x" is (on a leg) c^2 - b^2 = a^2. First take the square of 67 and 17
67 squared is 4489 and 17 squared is 289 then subtract both results
4489-289 = 4200 take the square root of this number
64.8074 (Round to the tenths 64.8)
In what I know of this problem and what you told me I think there is a 1/2 chance!
think about it, if the life span is 15 years old with standard deviation of 3 then that means we can have bats from 12~18 years old and the mean of the 50 numbers can be anything between that depending on the results we got. Then half of values in interval 12~18 is over 15 which gives it a 1/2 probability!
Answer:
Step-by-step explanation:
So this is our question
therefore we need to reduce the number of students for the food to be equivalent for 100 days so,
40 days → 150students
<h3> 100 days → </h3>
