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Angelina_Jolie [31]
2 years ago
9

Select the expressions

Mathematics
2 answers:
natulia [17]2 years ago
4 0
I believe it is the first one that is correct
yuradex [85]2 years ago
3 0
40+35 is the answer of the Ixl question
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Help with 19,20,21,23 please i don't understand geometry at all
Murrr4er [49]
19.  What you know is that HK+KJ = HJ.  If HJ = 25, the sum of the two equations will equal this length.  

x-5+5x-12=25  First, combine your like terms.  You will end up with 6x-17=25.  Add the opposite of -17 to both sides.  6x = 42  Divide both sides by 6.  x = 7.  Substitute x=7 for your original expression of x-5, 7-5=2

20.  (5x-6)/2 = x+6  Multiply each side by 2.  5x-6 = 2x +12  Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well.  3x = 18 Finally divide each side by 3.  x=6   To find the length of the remaining segment, substitute this value into (5x-6)/2.  This results in each side equaling a distance of 12.

21.  On the number line, the distance of FG is 16 units.  If the distance of FP is 1/4 of FG, you would simply divide 16 by 4.  The distance of FP is 4 and P lies at 8 on your number line.

23. The distance of SP is x+4 and ST=4x.  Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x.  Balance and solve for x, subtract 2x from both sides. 8=2x  Divide each side by 4, 8/4 = 4x/4 resulting in x=2.  If ST equals 4x, substitute and solve, 4(2) = 8
8 0
3 years ago
Use the law of cosines to find the length of side C.
sergij07 [2.7K]

Answer:

\text{D. 36.64}

Step-by-step explanation:

The Law of Sines is given by \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} and works for any triangle.

Therefore, we have the proportion:

\frac{c}{\sin 41.5^{\circ}}=\frac{37}{\sin 42^{\circ}},\\\\c=\frac{37\sin 41.5^{\circ}}{\sin 42^{\circ}}=36.6399945706\approx \boxed{36.64}

8 0
3 years ago
What are the solutions of the quadratic equation below? -7x2 - 23x + 10 = 0 A. B. C. D.
-BARSIC- [3]

Answer:

There are no like terms.

7 0
3 years ago
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Orlando's sports-card collection features players from four teams, as shown in the table below
alukav5142 [94]

Answer:D

Step-by-step explanation:

Sorry Ik it’s to late lol

8 0
3 years ago
Aisha recorded the heights, in centimetres, of some girls.
sertanlavr [38]

Answer:

The median is marked at 161cm instead of 162cm.

The right part of the box (the upper quartile) is marked at 172cm, while the interquartile range is 17cm, so the upper quartile should be at 154cm + 17cm = 171cm.

5 0
3 years ago
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