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Angelina_Jolie [31]
2 years ago
9

Select the expressions

Mathematics
2 answers:
natulia [17]2 years ago
4 0
I believe it is the first one that is correct
yuradex [85]2 years ago
3 0
40+35 is the answer of the Ixl question
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What is the factored form of the quadratic equation y=x2+4x-12? <br><br> PLEASE HELP ME!!!
snow_tiger [21]

Answer:

(x + 6)(x - 2)

Step-by-step explanation:

The given quadratic equation is $ y = x^2 + 4x - 12 $.

A quadratic equation can be factored in the form $ (x - a) (x - b) $ where $ -a $ and $ -b $ will form the roots of the equation

Here the roots are $ - 6 $ and $ 2 $.

The factored form would simply be: $ (x + 6) (x - 2) = 0 $.

Thus the answer.

4 0
3 years ago
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A car traveled 180 miles at a constant rate. Write an equation that would
Mnenie [13.5K]

Answer:

180/t = r

Step-by-step explanation:

In this question, we would have to write an equation that represents the scenario given.

We know that the car traveled 180 miles at a constant rate.

We would use the y = mx + b format for the equation, but replacing the variables with "r" and "t"

We know that 180 will be our y-variable, since that would be the base of the equation:

180 = ???

And to find how long/fast it will take the car, we would need to multiply the rate of speed "r" and time "t" in order to get our distance.

Plug it into the equation:

180 = rt

With this set up, you can find the rate of speed of the car when you know the time.

You would simply solve it as:

180/t = r

7 0
3 years ago
If x = 3, calculate the value of: x3 - x
Sergeeva-Olga [200]
You have to fill in 3 for x so it woul look like 3x3-3 and that would be 6.
8 0
3 years ago
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Please help me its a math problem !! please see image
erma4kov [3.2K]

Answer:

<u>y ≤ 4</u>

Step-by-step explanation:

Solving :

  • Highest y-value is 4
  • The other y-values are less than 4
  • Hence, the range is : <u>y ≤ 4</u>
5 0
1 year ago
What is the answer please, thanks
Alex787 [66]
748 inches... You do know there's a meter to inches converter online, right?
3 0
3 years ago
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