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2 years ago

2. choosing rye or Bermuda grass and 3 different mixtures of fertilizer Please help :(

Mathematics

1 answer:

const2013 [10]2 years ago

8 0

Answer:

oof im so sorrry, good luck with the test

Step-by-step explanation:

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The sum of the angle measures of a polygon with s sides is 2340. find s.

marta [7]

Answer:

s = 15.

Step-by-step explanation:

The formula for a polygon with s sides is:

Sum of the angles = 180(s - 2) so we have:

180(s - 2) = 2340

180s - 360 = 2340

180s = 2700

s = 15

8 0

3 years ago

Help w #5 !! will mark brainlist

iris [78.8K]

The sum that represents the number of tickets sold if 35 tickets were sold Monday, half of the remaining tickets were sold on Tuesday and 14 tickets were sold on Wednesday.

To start solving this, we can assign t as the variable to the total number of tickets that were sold. So, t = 35 (for Monday) + (t - 35)/2 (for Tuesday) + 14 (for Wednesday). To solve this, we can say t = 49 + (t - 35)/2, or 2t = 98 + t - 35, which equals t = 63. Therefore, 63 tickets were sold total.

7 0

3 years ago

Can there be more than,less than,or exactly one cup of water in a kitchen sink?

yulyashka [42]

Hello! Welcome to Brainly!

There would be more than.

A kitchen sink can hold approximately nine gallons of water.

Hope this helps you out fam!

~theLocoCoco

4 0

3 years ago

Read 2 more answers

Simplify the following fraction 20/14

Alex_Xolod [135]

I HOPE THE ABOVE INFORMATION WILL HELP YOU.

Thank you.

Teddy lover ❤❤

7 0

2 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago