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cupoosta [38]
2 years ago
13

There are 12 pounds of dirt to be shared equally among 8 flowerpots.

Mathematics
1 answer:
fomenos2 years ago
4 0

Answer:

1 1/2

Step-by-step explanation:

Brainiest please

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Can someone give me the steps to solving this equation? 3^x = 81
r-ruslan [8.4K]
Do 81/3=27/3=9/3=3, So you see the answer is 3^<span>4, I don't know if that's the official way to solve it but it works.</span>
5 0
3 years ago
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mylen [45]
1 is for circle
2 is for triangle
3 is for surface area
4 is for volume
5 0
3 years ago
4. What is the circumference of a circle whose area is 81π cm squared?
vichka [17]
Area = pi*r^2
Circumference = 2pi*r

Step 1: find the radius from area
81pi=pi*r^2
81=r^2
9=r

Step 2: plug in radius to the circumference equation

Circumference = 2pi*r

18pi is the answer, otherwise know as 56.52 as well.
7 0
2 years ago
Read 2 more answers
1. Find the measure of the side indicated (x). Round to the nearest tenth. Show your work to support your
lidiya [134]

Answer:

Is this for a Trig class?  just wondering

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

we want to find the Hypotenuse (Hyp)  and are given an angle and the adjacent side (adj)  sooo use  CAH  , b/c it has all of the pieces

Cos(37) = Adj / Hyp

Cos(37) = 11 / Hyp

swap  Cos(37) and Hyp... an algebra trick you should know from college algebra or where ever you learned algebra

Hyp = 11 / Cos(37)

now solve with your handy TI 83 / 84 / 89   calculator :)  if you don't have one go get one . :D get the 89 if  you are going into engineering classes...  the 83 /84 if not. (obviously there are many many other good choices, i'm not really a calculator salesman on the side :D )

Hyp = 13.77349...

Hyp = 13.8 ( rounded to nearest 10th )  :)

3 0
3 years ago
(30 points)
Pani-rosa [81]

The vertices of the triangle are the points where any pair of lines intersect.

We start by setting up the system

\begin{cases}y=-x+2\\y=2x-1 \end{cases} \iff -x+2=2x-1 \iff 3x=3 \iff x=1

Using one of the two equations we can derive the correspondent y value:

f(x)=-x+2 \implies f(1)=-1+2 = 1

So, one vertex is (1, 1)

We choose the other two pairs of lines to find the other vertices:

\begin{cases}y=-x+2\\y=x-2 \end{cases} \iff -x+2=x-2 \iff x=2 \implies y = 0

\begin{cases}y=x-2\\y=2x-1 \end{cases} \iff x-2=2x-1 \iff x=-1 \implies y=-3

So, the three vertices are (1, 1), (2, 0), (-1, -3).

8 0
2 years ago
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