Question

HELPPPP PLEASEEE IM BEGGING SOMEONE PLEASE PLEASE HELP

Answer 1

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

$m\angle RPS=90^\circ$                       [Right angle]

$(5x+15)^\circ=90^\circ$

$(5x+15)=90$

$5x=90-15$

$5x=75$

Divide both sides by 5.

$x=\dfrac{75}{5}$

$x=15$

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

$m\angle RQP=(2x+3)^\circ$

Putting $x=15$, we get

$m\angle RQP=(2(15)+3)^\circ$

$m\angle RQP=(30+3)^\circ$

$m\angle RQP=33^\circ$

Therefore, the measure of angle RQP is 33 degrees.