Answer:
The area of the quadrilateral ABCD is 114 square units
Step-by-step explanation:
We must calculate the area of each triangle and then add these areas so we calculate the area of the quadrilateral ABCD
First for the BAD right triangle:
AD = sqrt [BD ^ 2 - AB ^ 2]
AD = sqrt [15 ^ 2 - 12 ^ 2]
AD = sqrt [225-144]
AD = sqrt [81]
AD = 9
The area of a triangle is half the product of the base times the height, that is:
A1 = AB * AD / 2 = 12 * 9/2 = 54
Then for the second triangle in the right triangle BDC:
DC = sqrt [BC ^ 2 - BD ^ 2]
DC = sqrt [17 ^ 2 - 15 ^ 2]
DC = sqrt [289 - 225]
DC = sqrt [64] = 8
We calculate the area
A2 = DC * BD / 2 = 8 * 15/2 = 60
The total area then is:
AT = A1 + A2
AT = 54 + 60 = 114
Which means that the area of the quadrilateral ABCD is 114 square units
Answer:
360
Step-by-step explanation:
v = length x width x height
v = 15 x 8 x 3
v = 360
Step-by-step explanation:
5/6×12..1/5 x 100cm(1m)
i think so dont hate me
Answer:
-46
Step-by-step explanation:
4 - 2(a^2 – b^2)^2 =
= 4 - 2(3^2 – 2^2)^2
= 4 - 2(9 - 4)^2
= 4 - 2(5)^2
= 4 - 2(25)
= 4 - 50
= -46
Answer:
7282
Step-by-step explanation:
To answer this use PEMDAS
First, we need to multiply: 76 x 94 = 7144
Then we add: 7144 + 138 = 7282