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AlladinOne [14]
3 years ago
13

The lines in the graph of part A don't intersect at two whole numbers on the coordinate grid. Estimate the values of the solutio

n to the nearest one-fourth of a unit. Then substitute the x- and y-values of the approximate solution into the two equations. How close do you get to the constant numbers in each equation?

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

The solution lies at approximately (4.25,6.5).

Step-by-step explanation:

The estimate is pretty close for both equations. For the first equation, the estimate results in a value that is only 0.2125 units away from the constant. For the second equation, the estimate results in a value that is only 0.25 units away from the constant.

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Given:

The figure of two quadrilaterals.

In ABCD,AB=18,BC=20,CD=22,AD=24

In EFGH,EF=27,FG=30,GH=34, EH=36

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

\dfrac{AB}{EF}=\dfrac{18}{27}

\dfrac{AB}{EF}=\dfrac{2}{3}

Similarly,

\dfrac{BC}{FG}=\dfrac{20}{30}

\dfrac{BC}{FG}=\dfrac{2}{3}

\dfrac{CD}{GH}=\dfrac{22}{34}

\dfrac{CD}{GH}=\dfrac{11}{17}

And,

\dfrac{AD}{EH}=\dfrac{24}{36}

\dfrac{AD}{EH}=\dfrac{2}{3}

Clearly, \dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}.

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

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