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Dovator [93]
3 years ago
13

A rectangular piece of cheese is 9 centimeters long is 5 centimeters wide. What is the perimeter

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Solution:

<u>We know that:</u>

  • Perimeter of rectangle = 2L + 2B

<u>Given:</u>

  • L = 9 cm
  • W = 5 cm

<em>Substitute the values into the expression to find the perimeter.</em>

  • Perimeter of rectangle = 2L + 2B
  • => 2(9) + 2(5)
  • => 18 + 10
  • => 28 cm
sesenic [268]3 years ago
4 0

Answer: 28cm

Step-by-step explanation:

The perimeter formula for a rectangle = 2(l + w); where:

length = 9cm

width = 5cm

P = 2(l + w)

= 2(9 + 5)

= 18 + 10

= 28cm

Therefore, the perimeter of the cheese is 28cm

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In each of the following equations, what is y when z=2? When x = 0? Where would the graph of each equation cross the y-axis? Hom
Lelechka [254]

Answer:

a. y = 3 × 0 + 15

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5 0
2 years ago
The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?
Alexxx [7]

Answer:

Perimeter = 22.809836694575                              

Step-by-step explanation:

A(-2, 2)  ;  B(6,2)  ;  C(0, 8)

AB=\sqrt{\left( 6--2\right)^{2}  +\left(2-2 \right)^{2}  } =\sqrt{64} =8

AC=\sqrt{\left( 0--2\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{40} =2\sqrt{10}

BC=\sqrt{\left( 0-6\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{72} =6\sqrt{2}

Then

The perimeter of ΔABC = AB + BC + AC

                                       =8+6\sqrt{2} +2\sqrt{10}

                                       = 22.809836694575

3 0
3 years ago
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