Answer:
-22y+27
Step-by-step explanation:
(4y-9)(2y-3)
<u>Distribute:</u>
8y-12y-18y+27
<u>Combine like terms:</u>
8y-12y-18y=-22y
-22y+27
Answer: 1 3/4 is your mixed fraction and 7/4 is the improper fraction.
Step-by-step explanation:
Answer:
(a) The system of the equations
has no solution.
(b) The system of the equations
has many solutions 
Step-by-step explanation:
(a) To find the solutions of the following system of equations
you must:
Multiply
by 2:

Subtract the equations

0 = -3 is false, therefore the system of the equations has no solution.
(b) To find the solutions of the system
you must:
Isolate x for 

Substitute
into the second equation

The system has many solutions.
Isolate y for 

Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN