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alexira [117]
3 years ago
13

Butane (C4H10) reacts with oxygen in the air

Chemistry
1 answer:
damaskus [11]3 years ago
3 0
58.0 g butane in oxygen will produce 3.99 mol carbon dioxide .
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3 years ago
The human body needs at least 1.03 x 10-^2 mol O2 every minute. If all of this oxygen is used for the
Neko [114]
<h3>Answer:</h3>

0.3093 g of glucose are consumed each minute by the body.

<h3>Explanation:</h3>
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  • The equation for the reaction taking place during cellular respiration is;

C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂

We are required to calculate the amount of glucose in grams;

<h3>Step 1: Calculate the moles of glucose broken down</h3>

From the equation, the mole ratio of glucose to Oxygen is 1 : 6

Moles of Oxygen in a minute is 1.03 × 10^-2 moles

Therefore, moles of glucose will be;

= (1.03 × 10^-2)÷6

= 1.717 × 10^-3 moles

<h3>Step 2: Mass of glucose </h3>

Mass is given by multiplying the number of moles with molar mass

mass = moles × molar mass

Molar mass glucose is 180.156 g/mol

Therefore;

Mass = 1.717 × 10^-3 × 180.156 g/mol

         = 0.3093 g

Hence, 0.3093 g of glucose are consumed each minute by the body.

3 0
4 years ago
What is the Mr of a substance where 1 mole has a mass of 11 g?
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Answer:

A mole is the amount of pure substance containing the same number of chemical units as there are atoms in exactly

12 grams of carbon-12 (i.e., 6.023 X 1023).

Explanation:

6 0
3 years ago
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