Answer:it is 3 just look at the middle numbers
Explanation:
Pressure of Butane in the container at 135°C = 1.07 atm
Given:
The H°vap of butane is 24.3 kJ/mol.
starting out at 25 °C
Temperature at the end: 135 °C
2.3 atm of pressure
To Find:
The container's pressure
The perpendicular force per unit area, also known as the stress at a point within a confined fluid, is known as pressure in the physical sciences.
Equation of Clausius-Clapeyron
P2 = 1.07 atm and ln (P2/2.3 atm)
= - 24.3*110/8.31
The pressure in the container at 135°C (ΔH°vap ) is 1.07 atm
Learn more about Pressure here:
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Answer: a. A worm can move so it must be living.
Explanation:
If a worm is moving it is classified as a moving worm also known to be living if moving.
A worm could reproduce therefore it is living.
Worms do pass dirt into and through there bodies to eat of the minerals and discarding things through and let out.
If you do cut a worm in half it may damage it but since it has basically two heads on girl one boy and cut in half it may split them up, and make damage but they will eventually grow back if the injuries are not severe.
I Gave Some Facts and I Hope This Will Help!
HAPPY NEW YEAR!
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We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, 
moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
