Write the equation that represents the line that goes through the point (5, -7) and has slope m=-3

Mathematics

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

y = -3x + 8

Step-by-step explanation:

Given :-

Point on line = (5, -7)

Slope (m) = -3

To find :-

Equation of line

Solving :-

Using point-slope form of equation,

y - y₁ = m(x - x₁)

y + 7 = -3(x - 5)

y + 7 = -3x + 15

Solution :-

y = -3x + 8

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Which is the best estimate for the average rate of change for the quadratic function graph on the interval 0 ≤ x ≤ 4?

den301095 [7]

ANSWER

A) -1

EXPLANATION

The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).

That is the average rate of change is:

$= \frac{f(4) - f(0)}{4 - 0}$

From the graph, f(0) is 0 and f(4) is -4.

We plug in these values to obtain;

$= \frac{ - 4 - 0}{4 - 0}$

This simplifies to;

$= \frac{ - 4}{4}$

$= - 1$

Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1

5 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csf%202x%2B21%3D3" id="TexFormula1" title="\sf 2x+21=3" alt="\sf 2x+21=3" align="absmiddle"

sergij07 [2.7K]

$\sf \longmapsto \: 2x + 21 = 3$