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Arturiano [62]
3 years ago
11

Order the situations from the account that yields the greatest amount to one that yields the least amount.

Mathematics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

Order from the greatest yield to the least as follows

1. Situation B=$2,119.8949

2. Situation A=$2,095.3078

3. Situation C=$2,022.7789

Step-by-step explanation:

Situation A

A=P(1+r/n)^nt

=500(1+0.12/12)^12*12

=500(1+0.01)^144

=500(1.01)^144

=500(4.1906155936008)

=$2,095.3078

Situation B

A=P(1+r/n)^nt

=500(1+0.1/4)^4*15

=500(1+0.025)^60

=500(1.025)^60

=500(4.3997897488150)

=$2119.8949

Situation C

A=P(1+r)^t

=500(1+0.15)^10

=500(1.15)^10

=500(4.0455577357079)

=$2022.7789

Order from the greatest yield to the least as follows

1. Situation B=$2,119.8949

2. Situation A=$2,095.3078

3. Situation C=$2,022.7789

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First, we would need to figure out how many shelves are needed to build 1 bookcase. To do that, you would need to divide the number of shelves by the number of bookcases it can make.

65 ÷ 13 = 5

Now we know, it takes 5 shelves to build a single bookcase.  The next step would be to find out how many shelves it would take to build 6 more bookcases.  To find the answer, you would multiply the number of shelves it takes to build 1 bookcase by the number of bookcases that need to be built.

5 x 6 = 30

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