+3=17

Mathematics

1 answer:

aev [14]2 years ago

5 0

Answer:

Step-by-step explanation:

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There are 24 boys and 16 girls in a hall, each holding coins in their hand.

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

total=average ×no.

18×40=720 the no. of coins for all children

12×24=288 no. of coins for boys

720-288=432 for all girls

one girl, mean,divide 432 by 16= 27

5 0

3 years ago

Which rule describes the function in the graph below?

m_a_m_a [10]

The function that models the graph is given as: $f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3} \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \ 4 < x < 7 \right.$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation shown in the graph represents a piecewise function. Hence:

From the line through the point (-8, 4) and (-2, 2), the equation is f(x) = -(1/3)x + 4/3

From the curve through the point (-2, 2) and (0, 6), the equation is f(x) = -x² + 6

From the line through the point (0, 6) and (4, 6), the equation is f(x) = -6

From the line through the point (4, 6) and (7, 9), the equation is f(x) = x + 2

The function that models the graph is given as: $f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3} \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \ 4 < x < 7 \right.$

Find out more on equation at: brainly.com/question/2972832

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3 0

2 years ago

A segment with endpoints A (2, 1) and C (4, 7) is partitioned by a point B such that AB and BC form a 3:2 ratio. Find B.

sdas [7]

$\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ A(2,1)\qquad C(4,7)\qquad \qquad \stackrel{\textit{ratio from A to C}}{3:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{3}{2}\implies \cfrac{A}{C} = \cfrac{3}{2}\implies 2A=3C\implies 2(2,1)=3(4,7)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill$

$\bf B=\left(\cfrac{(2\cdot 2)+(3\cdot 4)}{3+2}\quad ,\quad \cfrac{(2\cdot 1)+(3\cdot 7)}{3+2}\right)\implies B=\left( \cfrac{4+12}{5}~,~\cfrac{2+21}{5} \right) \\\\\\ B=\left(\cfrac{16}{5}~~,~~\cfrac{23}{5} \right)\implies B=\left( 3\frac{1}{5}~~,~~4\frac{3}{5} \right)$