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Alona [7]
3 years ago
5

How to solve vatiable equations 5x-7=7x-17

Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
Let's get the same terms on the same side.
I am going to remove 5x from both sides of the equation by subtracting 5x

5x - 5x -7 = 7x -5x - 17
           -7 = 2x - 17   now lets remove the 17 from both sides
       -7 + 17 = 2x     (why do we add 17?  Think of 2x -17 as 2x +  -17.  Tor remove a negative number we add it.
Now we finally have     10=2x and if we divide both sides by 2

<u>10</u>  = <u>2x</u><u>
</u>2       2    we get that x = 5
<u />Let's check by substituting 5 in the original equation:
5(5) - 7 = 7(5) - 17
25 - 7 = 35 - 17
18      =       18
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4 0
3 years ago
Need help Urgently, Easy question<br><br> Find x.
alexira [117]
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8 0
3 years ago
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How many pennies could you have if: When you Break de Pennies into groups of 2, you have 1 penny left over, AND when you break t
MariettaO [177]

Answer:

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is  not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

6 0
3 years ago
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(using distribution property)

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