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2 years ago

How to solve vatiable equations 5x-7=7x-17

1 answer:

3 0

Let's get the same terms on the same side.
I am going to remove 5x from both sides of the equation by subtracting 5x

5x - 5x -7 = 7x -5x - 17
-7 = 2x - 17 now lets remove the 17 from both sides
-7 + 17 = 2x (why do we add 17? Think of 2x -17 as 2x + -17. Tor remove a negative number we add it.
Now we finally have 10=2x and if we divide both sides by 2

<u>10</u> = <u>2x</u><u>
</u>2 2 we get that x = 5
<u />Let's check by substituting 5 in the original equation:
5(5) - 7 = 7(5) - 17
25 - 7 = 35 - 17
18 = 18

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Do waves move matter as they travel?

umka2103 [35]

Answer:

No.

Step-by-step explanation:

Waves are energy moving through the matter, but they leave the matter in the same place as they pass through.

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2 years ago

Researchers capture and mark 43 squirrels in a park. The next week, researchers capture 50 squirrels and 38 of them are marked f

Vlada [557]

The question is an illustration of sample and population, and the estimate of the population of squirrel in the park is 55

<h3>How to determine the population of squirrel?</h3>

The given parameters are:

Marked squirrels = 43

Captured squirrels = 50

Of the 50 captured squirrels, 38 are from the marked squirrels.

This means that the number of unmarked squirrels is:

Unmarked = 50 - 38

Evaluate

Unmarked = 12

The population of the squirrel is then calculated using:

Population = Marked + Unmarked

So, we have:

Population = 43 + 12

Evaluate the sum

Population = 55

Hence, the estimate of the population of squirrel in the park is 55

Read more about population at:

brainly.com/question/7301139

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1 year ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

2 years ago

The equation $y=-4.9t^2+3.5t+5$ describes the height (in meters) of a ball thrown upward at $3.5$ meters per second from $5$ met

Georgia [21]

Answer:

Step-by-step explanation:

The position function is

$s(t)=-4.9t^2+3.5t+5$ and if we are looking for the time t it takes for the ball to hit the ground, we are looking for the height of the ball when it is on the ground. Of course the height of anything on the ground is 0, so if we set s(t) = 0 and solve for t, we will find our answer.