Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence
here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.
Answer: 2 and 2/3
Step-by-step explanation: In this problem, we have 2/3 ÷ 1/4.
Dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the divison sign to multiplication and flip the second fraction.
So here, 2/3 ÷ 1/4 can be rewritten as 2/3 × 4/1.
Now we are simply multiplying fractions so we multiply across the numerators or top number number and multiply across the denominators or bottom numbers.
8/3 can be converted into a mixed number by dividing the denominator of the fraction into the numerator of the fraction.
3 divides into 8 2 with a remainder of 2 times so our whole number will be 2 and our new numerator will be 2 as well. We will put this over our original denominator which is 3. Now we have 2 and 2/3.