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Scilla [17]
3 years ago
7

I need help quickly!!

Mathematics
2 answers:
allsm [11]3 years ago
6 0

Answer:

c. 73°

Step-by-step explanation:

Simply GNH is 47° by vertically opposite angle of MNL

NOW,

GNF+GNH+HNK=180° [ being straight line]

60+47+HNK=180

107+HNK=180

HNK=180-107=73

Ad libitum [116K]3 years ago
6 0
C. 73 degrees hope this helps
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What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.
lapo4ka [179]

Consider the equation x^6+6x^3+5=0.

First, you can use the substitution t=x^3, then x^6=(x^3)^2=t^2 and equation becomes t^2+6t+5=0. This equation is quadratic, so

D=6^2-4\cdot 5\cdot 1=36-20=16=4^2,\ \sqrt{D}=4,\\ \\ t_{1,2}=\dfrac{-6\pm 4}{2} =-5,-1.

Then you can factor this equation:

(t+5)(t+1)=0.

Use the made substitution again:

(x^3+5)(x^3+1)=0.

You have in each brackets the expression like a^3+b^3 that is equal to (a+b)(a^2-ab+b^2). Thus,

x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)

and the equation is

(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0.

Here x_1=-\sqrt[3]{5} , x_2=-1 and you can sheck whether quadratic trinomials have real roots:

1. D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}.

2. D_2=(-1)^2-4\cdot 1=1-4=-3.

This means that quadratic trinomials don't have real roots.

Answer: x_1=-\sqrt[3]{5} , x_2=-1

If you need complex roots, then

x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2}   ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}.

6 0
4 years ago
What's the equation of the line in y=mx+b form?​
ozzi

Answer:

Y=2/3x-1

Step-by-step explanation:

5 0
3 years ago
Can someone help me with Thai I don’t know how to do it and I’m struggling with this online stuff
elena-14-01-66 [18.8K]

Answer:

11\frac{170}{333}

Step-by-step explanation:

let x=11.510510510...

multiply by 1000

1000x=11510.510510...

again multiply by 1000

1000,000 x=11510510.510510...

subtract

999,000 x=1,1 49 9,000

x=11,499,000/999000=3,833,000/333,000=3833/333

333 ) 3833 (11

       -333

       --------

          503

        - 333

        -------

          170

         ------11\frac{170}{333}

7 0
4 years ago
2h = W-3p<br> (solve for p)
Alex_Xolod [135]

Answer:

p = (2h-W)/-3

Step-by-step explanation:

2h - W = -3p

divide both sides by -3

(2h-W)/-3 = p

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3 years ago
You know whats weird lol?
irga5000 [103]

Answer:

wow

Step-by-step explanation:

6 0
3 years ago
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