1) 1
2)1600
3)0.109
4)0.250
5)14000
6)1000
7)4.8
8)0.027
9)0.198
10)0.075
11)0.50
12)5000
13)1.6
14)65000
15)25
16)0.355
17)0.08
18)63
19)560
20)260
21)0.0565
22)0.0275
23)9.23
24)2500
It was fun!
Mass of Copper : 63.5 g
<h3>Further explanation</h3>
Given
Reaction
Cu(s)+2AgNO₃ (aq) ⇒Cu(NO₃)₂ (aq)+2Ag(s)
Required
Mass of Copper
Solution
mol of Silver nitrate :
= M x V
= 2 mol/L x 0.5 L
= 1
From the equation, mol ratio of Cu : AgNO₃ = 1 : 2, so mol Cu = 1
Mass of Cu(Ar=63.5 g/mol) :
= mol x Ar
= 1 x 63.5
= 63.5 g
Answer:
n = 3.0 moles
V = 60.0 L
T = 400 K
From PV = nRT, you can find P
P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L
P = 1.642 atm = 1.6 atm (to 2 significant figures)
Explanation:
Strong electron withdrawing groups prevents Friedel Crafts reaction because when a withdrawing group attracts the electrons decrease the availability of the electronic pair and the enough electronic density of it in order to make possible the aromatic electrophilic substitution.
Strong electron donating groups like NH2 doesn’t undergo Friedel Crafts reaction because NH2 is a Lewis base that means an electron donor. Due to Friedel Crafts reaction is an acid base reaction, the AlCl3 will be attacked by the lone pair available from NH2 producing a salt. The same occurs with phenol because the lone pair of electrons available in the OH group so Friedels Crafts doesn’t undergo with benzene attached to the strong electron donating groups NH2 or OH.
