All the given species have the same charge except peroxide.
<h3>Charges on ions</h3>
- The charge on monohydrogen phosphate is negative because of its formula,
.
- The charge on permanganate is negative. The formula is

- The charge of oxide (
) is negative.
- The charge on peroxide is ( R−O−O−R) is neutral.
- The charge on oxalate,
, is negative.
Thus, only peroxide is unique.
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Answer:
diiodomethane
Explanation:
The densities of each of the liquids mentioned in the question are stated below;
CCl4- 1.59 g/cm^3
Hexane- 0.672 g/cm^3
Benzene- 0.8765 g/cm^3
Diiodomethane- 3.3 g/cm^3
Clearly, the density of diiodomethane methane is almost the same as that of the desired granular material, hence the undesired granular material having a density of 2.04 g/cm3 will float in diiodomethane thus separating the two granular materials.
Answer:
Choice 'B'
Explanation:
Choice B => SCl₂ => 2 bonded pairs + 2 nonbonded pairs => 4 electron pairs => AX₄ parent => tetrahedral parent, but the shape is defined only by what's bonded to the central element that is, sulfur bonded to two Cl substrates. The electron pairs will assume positions in space (to minimize repulsion forces) like a regular tetrahedron (AX₄) but will have an AX₂E₂ geometry which is a Bent Geometry.
Suggest searching molecular geometry images online. Look for derivatives of AX₄ geometries. Example: H₂O (AX₂E₂ bent geometry; also a derivative of AX₄ tetrahedral parent geometry).
Answer:
Final molarity = 6 M
Explanation:
Given data:
Initial volume = 0.50 L
Initial molarity = 12 M
Final volume = 1 L
Final molarity = ?
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume
M₂ = Final molarity
V₂ = Final volume
Now we will put the values.
12 M × 0.50 L = M₂ × 1 L
6 M.L = M₂ × 1 L
M₂ = 6 M.L / 1L
M₂ = 6 M