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earnstyle [38]
3 years ago
5

Looking across period 4 of the periodic table, potassium (atomic number 19) is followed by calcium (atomic number 20), which is

followed by scandium (atomic number 21). Which element should have the largest atomic radius? A) potassium B)calcium C)scandium D)All three have the same atomic radius.
Chemistry
2 answers:
Mumz [18]3 years ago
8 0
While staying in the same period, if we move from left to right across the period, the atomic radius decreases. The reason is, in a period the number of shells remain the same and the number of electrons and protons increase as we move across the period to the right. The increased electrons and protons attract each other with greater force and hence the atomic size decreases. 

So the element on the left most will have the largest atomic radius. So the correct ans is Potassium. Potassium will have the largest atomic size among Potassium, Calcium and Scandium. 
svet-max [94.6K]3 years ago
8 0

Answer:

A.

Explanation:

Plato

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All the following ions have the same charge except Group of answer choices oxide. monohydrogen phosphate. peroxide. permanganate
Triss [41]

All the given species have the same charge except peroxide.

<h3>Charges on ions</h3>
  • The charge on monohydrogen phosphate is negative because of its formula, [HPO4]^{2-}.

  • The charge on permanganate is negative. The formula is MnO^-

  • The charge of oxide (O^{2-}) is negative.

  • The charge on peroxide is ( R−O−O−R) is neutral.

  • The charge on oxalate, C2O4^{2-}, is negative.

Thus, only peroxide is unique.

More on charges on ions can be found here: brainly.com/question/11938054

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4 0
2 years ago
Which of these is an example of a physical change?
Vikki [24]

Answer:

b metal denting

Explanation:

8 0
4 years ago
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You are assigned the task of separating a desired granular material, with a density of 3.26 g/cm3, from an undesired granular ma
Svetradugi [14.3K]

Answer:

diiodomethane

Explanation:

The densities of each of the liquids mentioned in the question are stated below;

CCl4- 1.59 g/cm^3

Hexane- 0.672 g/cm^3

Benzene- 0.8765 g/cm^3

Diiodomethane- 3.3 g/cm^3

Clearly, the density of diiodomethane methane is almost the same as that of the desired granular material, hence the undesired granular material having a density of 2.04 g/cm3 will float in diiodomethane thus separating the two granular materials.

5 0
3 years ago
Please help a brother out!
White raven [17]

Answer:

Choice 'B'

Explanation:

Choice B => SCl₂ => 2 bonded pairs + 2 nonbonded pairs => 4 electron pairs => AX₄ parent => tetrahedral parent, but the shape is defined only by what's bonded to the central element that is, sulfur bonded to two Cl substrates. The electron pairs will assume positions in space (to minimize repulsion forces) like a regular tetrahedron (AX₄) but will have an AX₂E₂ geometry which is a Bent Geometry.

Suggest searching molecular geometry images online. Look for derivatives of AX₄ geometries. Example: H₂O (AX₂E₂ bent geometry; also a derivative of AX₄ tetrahedral parent geometry).

3 0
3 years ago
When 0.50 liter of a 12m solution is diluted to 1.0 liters, the molarity of the new solution is ____
Akimi4 [234]

Answer:

Final molarity  = 6 M

Explanation:

Given data:

Initial volume = 0.50 L

Initial molarity = 12 M

Final volume = 1 L

Final molarity = ?

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume

M₂ = Final molarity

V₂ = Final volume

Now we will put the values.

12 M × 0.50 L = M₂ ×  1 L

6 M.L = M₂ ×  1 L

M₂ = 6 M.L / 1L

M₂ = 6 M

6 0
4 years ago
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