Answer:
93.5 kPa
Explanation:
Step 1: Given data
- Initial pressure (P₁): 81.0 kPa
- Initial temperature (T₁): 50 °C
- Final volume (T₂): 100 °C
Step 2: Convert the temperatures to the Kelvin scale
When working with gases, we need to consider the absolute temperature. We will convert from Celsius to Kelvin using the following expression.
K = °C + 273.15
T₁: K = 50°C + 273.15 = 323 K
T₂: K = 100°C + 275.15 = 373 K
Step 3: Calculate the final pressure of the gas
At a constant volume, we can calculate the final pressure of the gas using Gay-Lussac's law.
P₁/T₁ = P₂/T₂
P₂ = P₁ × T₂/T₁
P₂ = 81.0 kPa × 373 K/323 K
P₂ = 93.5 kPa
1 Hydrogen 1s1
2 Helium 1s2
3 Lithium 2s1
Answer:A
Explanation:
The melting points of solids depend in the relative sizes of ions in the ionic lattice. The smaller the relative sizes of the ions, the higher the lattice energy and the stronger the lattice hence higher melting point. Comparing relative ionic sizes, fluoride ion is lesser in size than chloride ion hence NaF has a higher melting point than NaCl.
What are the following measurements?
Answer:
-26.125 kj
Explanation:
Given data:
Mass of water = 250.0 g
Initial temperature = 30.0°C
Final temperature = 5.0°C
Amount of energy lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 5.0°C - 30.0°C
ΔT = -25°C
Specific heat of water is 4.18 j/g.°C
Now we will put the values in formula.
Q = m.c. ΔT
Q = 250.0 g × 4.18 j/g.°C × -25°C
Q = -26125 j
J to kJ
-26125 j ×1 kj /1000 j
-26.125 kj
