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Zigmanuir [339]
3 years ago
15

The rate constant for this first‑order reaction is

Chemistry
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

t = 5.7634 s

Explanation:

  • A → Pdts
  • - rA = K (CA)∧α = - δCA/δt

∴ T = 400°C

∴ α = 1 ....first-order

∴ CAo = 0.950 M

∴ CA = 0.300 M

⇒ t = ?

⇒ - δCA/δt = K*CA

⇒ - ∫δCA/CA = K*∫δt

⇒ Ln (CAo/CA) = K*t

⇒ t = Ln(CAo/CA) / K

⇒ t = (Ln(0.950/0.300)) / (0.200 s-1)

⇒ t = 1.1527 / 0.200 s-1

⇒ t = 5.7634 s

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What is the vapor pressure at 35°C of a solution made by dissolving 44.6 g of sucrose, C12H22O11, in 62.3 g of water? The vapor
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Answer:

The correct answer is 40.861 torr.

Explanation:

Based on the given information, the weight of the solute (sucrose) given is 44.6 grams, the weight of the solvent, that is, water given is 62.3 grams, and 42.2 torr is the vapor pressure of pure water.

Now the molecular weight of sucrose is 342 grams per mole, and the molecular weight of water is 18 grams per mole.

The mole fraction of solute will be,

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= 44.6 grams/342 grams per mole/62.3 grams/18 grams per mole + 44.6 grams/342 grams per mole

= 0.1304/3.461 + 0.1304

= 0.0363

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