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2 years ago

Select the graph that represents h=-16t2+80

Mathematics

1 answer:

hichkok12 [17]2 years ago

3 0

I cant see it is blury try to take another picture

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I’m so confused on how to do this -?

ANTONII [103]

Answer:

256

Step-by-step explanation:

any number to the 0 power equals 1, so r^0 equals 1

then, you have (4(1))^4

4×1=4

4^4=256

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3 years ago

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How to write in two other firms .326

Natalija [7]

0.3 + 0.02 + 0.006

 $(3 \times 10^{-1}) + (2\times 10^{-2}) + (6\times10^{-3})$

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3 years ago

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What is the domain of: x ≥ -2 x ≥ 0 x ≥ 2 all real numbers

777dan777 [17]

Your answer should be A!

I hope this helped!

If you have any further questions, please feel free to private message me!

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3 years ago

PLZZZ SOMEONE HELP MEE

olya-2409 [2.1K]

What grade homework is that?

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3 years ago

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Find the 75th term of the arithmetic sequence -17, -13, -9....

Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

Step-by-step explanation:

Given the sequence

$-17, -13, -9....$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4$

The difference between all the adjacent terms is the same and equal to

$d=4$

The first element of the sequence is:

$a_1=-17$

now substitute $d=4$ and $a_1=-17$ in the nth term of the sequence

$a_n=a_1+\left(n-1\right)d$

$a_n=4\left(n-1\right)-17$

$a_n=4n-21$

Now, substitute n = 75 in the $a_n=4n-21$ sequence to determine the 75th sequence

$a_n=4n-21$

$a_{75}=4\left(75\right)-21$

$a_{75}=300-21$

$a_{75}=279$

Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

3 0

3 years ago