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Zanzabum
3 years ago
7

Help please quick!!!!!!!!!!

Mathematics
1 answer:
devlian [24]3 years ago
6 0
B because it’s y intercept is 1 and in the equation there is a plus 1 and the line goes up 1 over 2 which is a slope of 1/2 like the equation
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FInd the length of DB and CD. Please help!
Lerok [7]

Step-by-step explanation:

DB length = 5 1/4 + 2/3

=21/4 + 2/3

= 63/12 + 8/12 = 71/12

CD length = 5 1/4 -2 = 3 1/4

3 0
2 years ago
Hey please help me if you can I would appreciate it
PolarNik [594]
This is a division problem.
You need to divide 51/2 by 3/2.

\dfrac{51}{2} \div  \dfrac{3}{2} =

= \dfrac{51}{2} \times  \dfrac{2}{3}

= \dfrac{51 \times 2}{2 \times 3}

= \dfrac{102}{6}

= 102 \div 6

= 17

Answer: Choice D.




6 0
3 years ago
Read 2 more answers
What is the slope between the two points?<br> (6,8 ) and (-3, 8 )
Marta_Voda [28]

Answer:

slope=0

Step-by-step explanation:

Slope (m) = ΔY /ΔX =0  

ΔX = -3 – 6 = -9

ΔY = 8 – 8 = 0

Distance (d) = √ΔX2 + ΔY2 = √81 = 9

Equation of the line:

y = 0x + 8

When x=0, y = 8

5 0
3 years ago
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Use an inequality to describe the interval of real numbers <br><br>(-3,8]
Naya [18.7K]
38 i think it means infinite
8 0
3 years ago
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
2 years ago
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