Ask question

Ask question

All categories

Morgarella [4.7K]

1 year ago

10

Adam and Tom share a sum of money in the ratio 18:17

1 answer:

Digiron [165]1 year ago

5 0

x = total amount split between Adam and Tom.

since we know the total amount split between both in a 18 : 17 ratio is "x", let's divide "x" by (18 + 17) and distribute accordingly to get the amount of each.

$\stackrel{Adam~received}{18\cdot \cfrac{x}{18+17}}\qquad \qquad \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that Adam got "5" more}}{ \stackrel{Adam}{18\cdot \cfrac{x}{18+17}}~~ = ~~\stackrel{Tom}{17\cdot \cfrac{x}{18+17}~~ + ~~5} }\qquad \implies \qquad \cfrac{18x}{35}~~ + ~~\cfrac{17x}{35}+5$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{35}}{35\left( \cfrac{18x}{35} \right)~~ = ~~35\left( \cfrac{17x}{35}+5 \right)}\implies 18x~~ = ~~17x+175\implies \boxed{x =175} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}}\implies \cfrac{17(175)}{35}\implies \blacktriangleright 85 \blacktriangleleft$

You might be interested in

Which is equivalent to 8x−y 3x8x-y 3x?

garri49 [273]

IT IS 2X IF U NEED SOME ELSE TELL ME

7 0

3 years ago

I need help finding the measure to each angle<br>

cestrela7 [59]

Answer:

(15x-2)°+( 7x+4)°=90° --> 15x-2°+7x+4°=90° --> 22x+2°=90° --> 22x=90°-2° --> 22x=88° --> x=88/22 --> x=4.

m/_BAC=(15x-2)°=15×4-2 =58°

m/_CAD=(7x+4)°=7×4+4= 32°.

8 0

2 years ago

How to answer this problem

Mumz [18]

Answer:

5 Degrees

Step-by-step explanation:

In order to find the median, you must put the temperatures in ascending order. The median is the number in the middle.

This week

65 71 73 73 73 74 75

Last Week

51 62 66 68 72 72 85

The median of This week is 73 while the median last week is 68.

73-68=5 degrees

3 0

3 years ago

Read 2 more answers

Evarado paid $1.12 for a doszen eggs at his local grocery store. Determine the cost of the eggs

Dimas [21]

Answer:

of a single egg or?

Step-by-step explanation:

5 0

2 years ago

Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur

stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.
$P(A \cap B)$ is the probability of both A and B happening.
P(A) is the probability of A happening.

In this problem:

Event A: Three heads.
Event B: Fair coin.

The probability associated with 3 heads are:

$0.5^3 = 0.125$ out of 0.5(fair coin).
1 out of 0.5(biased).

Hence:

$P(A) = 0.125 + 0.5 = 0.625$

The probability of 3 heads and the fair coin is:

$P(A \cap B) = 0.5(0.125) = 0.0625$

Then, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1$

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0

2 years ago