Question

A paperweight is shaped like a triangular pyramid. The base is an equilateral triangle. Find the surface area of the paperweight.

Answer 1

Answer:

The surface area of the paperweight is $SA=8.3\ in^2$

Step-by-step explanation:

we know that

The surface area of the triangular prism is equal to the area of its triangular base plus the area of its three triangular lateral faces

so

Find the area of its triangular base

$SA=\frac{1}{2}(2)(1.7)$

$SA=1.7\ in^2$

Find the area of its three triangular lateral faces

$SA=3[\frac{1}{2}(2)(2.2)]$

$SA=6.6\ in^2$

Adds the areas

$SA=1.7+6.6$

$SA=8.3\ in^2$