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lys-0071 [83]
2 years ago
15

Evaluate 8-2.A. -16B. -64C. -1/64D. 1/64 ​

Mathematics
1 answer:
makvit [3.9K]2 years ago
8 0

I'm assuming you meant to write 8^(-2) or 8^{-2} where the -2 is the exponent over the 8.

If my assumption is correct, then we use the rule a^{-b} = \frac{1}{a^b}

So,

a^{-b} = \frac{1}{a^b}\\\\8^{-2} = \frac{1}{8^2}\\\\8^{-2} = \frac{1}{64}

<h3>Answer: Choice D.  1/64</h3>
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What is the point slope form?<br><br> (8,9) m = 0.5<br><br> Please show work.
Simora [160]
<span>(8,9) m = 0.5
point slope form 
y - y1 = m (x - x1)
so
equation

y - 9 = 0.5(x - 8)

answer
</span>
y - 9 = 0.5(x - 8)
8 0
4 years ago
Find the value of x and y
djverab [1.8K]

Answer:

x = 8, y = 27

Step-by-step explanation:

Since both opposite lines are equal in length to each other, these opposite lines are parallel to each other.  The top line is parallel and same length as the bottom line and the left and right lines are also parallel and equal in length.

Based on that, the two left side angles must equal 180 and the right side two angles must equal 180.

(2y + 24) + (3y + 21) = 180

That's the same as 2y + 24 + 3y + 21 = 180

Simplify to 5y + 45 = 180

Subtract 45 from both sides

5y = 135

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7 0
3 years ago
3/4 x 12 I'm having a hard time multiplying fractions can some one help ​
aleksley [76]
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6 0
3 years ago
Read 2 more answers
Write the equation for the given information slope: -11, point (-1,20)​
Dimas [21]

Answer:

y = -11x + 9

Step-by-step explanation:

m = -11

x = -1

y = 20

Plug those values into the equation to find b: y = mx + b

20 = (-11)(-1) + b

---> b = 9

Plus m = -11 and b = 9 into y = mx + b

---> y = -11x + 9

4 0
3 years ago
I'm sorry I don't know how to do this problem, and its the only one I don't understand could anyone help me.
kolbaska11 [484]
You would multiply everything by 2. A dilation of 2 is an enlargement, or an increase in shape. If it was -2, it would be a reduction.

Multiply everything by 2:
(-2,3) = (-4,6) (3,4)= (6,8) (4,-1)= (8,-2)

I hope this helps you!

Brainliest answer is always appreciated!<span />
3 0
4 years ago
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