Question

Evaluate 8-2.A. -16B. -64C. -1/64D. 1/64 ​

Answer 1

I'm assuming you meant to write 8^(-2) or $8^{-2}$ where the -2 is the exponent over the 8.

If my assumption is correct, then we use the rule $a^{-b} = \frac{1}{a^b}$

So,

$a^{-b} = \frac{1}{a^b}\\\\8^{-2} = \frac{1}{8^2}\\\\8^{-2} = \frac{1}{64}$

Answer: Choice D.  1/64